There were 38 tubes containing exactly 40 Smarties. The observed distribution of yellow beans in these 38 tubes is given in the following table.
| Number of yellow beans | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ≥9 |
| Frequency | 0 | 2 | 10 | 6 | 7 | 5 | 2 | 5 | 1 | 0 |
Calculate the proportions of tubes of 40 Smarties that contain 0, 1, 2, . . . , 8,≥ 9 yellow beans. Give the proportions rounded to three decimal places.
Given is the following frequency distribution of yellow beans in these 38 tubes ,
| Number of yellow beans | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | ≥9 |
| Frequency | 0 | 2 | 10 | 6 | 7 | 5 | 2 | 5 | 1 | 0 |
To obtain the corresponding probability distribution of tubes of
40 Smarties that contain 0, 1, 2, . . . , 8,≥ 9 yellow beans,
and is obtained as follows,
| Number of Yellow Beans | Proportion of tubes of 40 Smarties |
| 0 | 0 |
| 1 | 1/38 = 0.026 |
| 2 | 10/38 = 0.263 |
| 3 | 6/38 = 0.158 |
| 4 | 7/38 = 0.184 |
| 5 | 5/38 = 0.132 |
| 6 | 2/38 = 0.053 |
| 7 | 5/38 = 0.132 |
| 8 | 1/38 = 0.026 |
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Answer : Above table is the required corresponding proportions of tube of 40 Smarties
There were 38 tubes containing exactly 40 Smarties. The observed distribution of yellow beans in these...
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