The electromagnetic wave that delivers a cellular phone call to a car has a magnetic field with an rms value of 2.0 × 10-10 T. The wave passes perpendicularly through an open window, the area of which is 0.24 m2. How much energy does this wave carry through the window during a 31-s phone call? help
The electromagnetic wave that delivers a cellular phone call to a car has a magnetic field...
The electromagnetic wave that delivers a cellular phone call to
a car has a magnetic field with an rms value of 1.90 10-10 T. The wave passes
perpendicularly through an open window, the area of which is 0.20
m2. How much energy does this wave carry through the
window during a 60-s phone call?
The electromagnetic wave that delivers a cellular phone call to a car has a magnetic field with an rms value of 1.8 × 10-10 T. The wave passes perpendicularly through an open window, the area of which is 0.23 m2. How much energy does this wave carry through the window during a 32-s phone call?
The electromagnetic wave that delivers a cellular phone call to a car has a magnetic field with an rms value of 1.30 × 10-10 T. The wave passes perpendicularly through an open window, the area of which is 0.39 m². How much energy does this wave carry through the window during a 41-s phone call? Joules
A sinusoidal electromagnetic wave from a radio station passes perpendicularly through an open window that has area of 0.550m^2. At the window, the electric field of the wave has an rms value 1.60E-2 V/m . How much energy does this wave carry through the window in a 30.0 s commercial?
A sinusoidal electromagnetic wave from a radio station passes perpendicularly through an open window that has area of 0.600 m2 At the window, the electric field of the wave has an rms value 0.0600 V/m Part A How much energy does this wave carry through the window during a 30.0-s commercial? Express your answer with the appropriate units. HA ? Value Units U= Request Answer Submit Provide Feedback Next>
A sinusoidal electromagnetic wave emitted by a cellular phone has a wavelength of 34.5 cm and an electric-field amplitude of 6.20×10−2 V/m at a distance of 350 m from the antenna. a)Calculate the frequency of the wave. b)Calculate the magnetic-field amplitude. c)Find the intensity of the wave.
A sinusoidal electromagnetic wave emitted by a cellular phone has a wavelength of 34.6 cm and an electric-field amplitude of 4.30×10−2 V/m at a distance of 340 m from the antenna. A- Calculate the frequency of the wave. B-Calculate the magnetic-field amplitude. C-Find the intensity of the wave. D-
A neodymium-glass laser emits short pulses of high-intensity
electromagnetic waves. The electric field of such a wave has an rms
value of Erms = 2.0 × 109 N/C. Find the average power of each pulse
that passes through a 1.6 × 10-5-m2 surface that is perpendicular
to the laser beam.
A neodymium-glass laser emits short pulses of high-intensity electromagnetic waves. The electric field of such a wave has an rms value of E 2.0 x 109 NIC. Find the average...
The magnetic field of an electromagnetic wave has a peak value of 5.0 × 10-10 T. What is the intensity of the wave? (c = 3.0 × 108 m/s, c = 3.00 × 108 m/s, μ0 = 4π × 10-7 T • m/A 1.0 × 10-13 W/m2 7.5 × 105 W/m2 1.5 × 10-5 W/m2 2.0 × 10-13 W/m2 3.0 × 10-5 W/m2
An electromagnetic wave with an electric field of 1400 N/C delivers 2.5 kJ of energy to a detector in 1.8 h. What is the area of the detector?