If a fixed-length simple pendulum is found to have 4 times the period on an unknown...

Question

Question

If a fixed-length simple pendulum is found to have 4 times the period on an unknown

planet’s surface (compared to Earth), what is the gravity on that planet?

science physics

Answer 1

Answer #1

Answer 2

Similar Homework Help Questions

If a fixed length simple pendulum is found to have three times the period on an...

If a fixed length simple pendulum is found to have three times the period on an unknown planet’s surface (compared to Earth), what is the acceleration due to gravity on that planet? Show your work.
4) a) Calculate the period of a simple pendulum if the length of the string is...

4) a) Calculate the period of a simple pendulum if the length of the string is g on the moon. gon Moon is 16of g on Earth. gon Earth = 9.8 m/s: 1.5 meter? b) Calculate the period of the simple pendulum if you take to Mars. g on Mars 3.7 m/s What is the ratio of the period of the above simple pendulum to the period of a simple pendulum which is 4 times longer? b) d) What happens...
Consider a simple pendulum: a bob on the end of a string. The length of the...

Consider a simple pendulum: a bob on the end of a string. The length of the string (assumed massless) is 85 ?? and has a period of 1.62 ?. Assuming this pendulum is on another planet rather than Earth (and the angles are small), determine, a. The gravitational acceleration, near the surface of the planet. b. The angular frequency.

5. What should you do to the length of the string of a simple pendulum to...

5. What should you do to the length of the string of a simple pendulum to double its period? 7. The acceleration of gravity gets smaller as you increase your distance from the center of the Earth. For example, if you go to a height that is one earth radius above the surface of the earth the acceleration of gravity is 2.45 m/s² (g/4.0). Is the period of a pendulum longer or shorter? 8.A pendulum makes 42 cycles in 50.0...
Question: The period of a simple pendulum is T=2π√(L/g) with L = length of the pendulum...

Question: The period of a simple pendulum is T=2π√(L/g) with L = length of the pendulum and g = gravity of earth. a.Derive the scaling law for the pendulum. b.How much would the period of the pendulum change when you decrease the characteristic dimension by a factor of 10?
A simple pendulum on the surface of the Earth has period T. On a different planet,...

A simple pendulum on the surface of the Earth has period T. On a different planet, the same pendulum has period 27. The free-fall acceleration on this planet is 04g O g/4 O2g O g/2

1. If placed at the surface of Earth, a physical pendulum has a period of 1.8...

1. If placed at the surface of Earth, a physical pendulum has a period of 1.8 seconds. What will be the period of the same pendulum at the surface of the Moon (gMoon = 1.62 m/s2)? The period at the Moon's surface, T = Units in s 2. The same pendulum is placed at the surface of an unknown planet X. What is the free fall acceleration at the surface of this planet if the pendulum has a period of 1.17...
The period of a simple pendulum in a grandfather clock on another planet is 1.80 s....

The period of a simple pendulum in a grandfather clock on another planet is 1.80 s. What is the acceleration due to gravity on this planet if the length of the pendulum is 1.00 m.
(a) What is the length of a simple pendulum that oscillates with a period of 2.6...

(a) What is the length of a simple pendulum that oscillates with a period of 2.6 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2? LE = LM = Enter a number. Im (b) What mass would you need to suspend from a spring with a force constant of 20 N/m in order for the mass-spring system to oscillate with a period of 2.6 s...

(a) What is the length of a simple pendulum that oscillates with a period of 3.0...

(a) What is the length of a simple pendulum that oscillates with a period of 3.0 s on Earth, where the acceleration due to gravity is 9.80 m/s2, and on Mars, where the acceleration due to gravity is 3.70 m/s2? LE = Lм %3 m (b) What mass would you need to suspend from a spring with a force constant of 20 N/m in order for the mass-spring system to oscillate with a period of 3.0 s on Earth, where...