Question

Show all your work, I WILL RATE!! Consider the following code: li $t0, 99 li $t1,...

Show all your work, I WILL RATE!!

Consider the following code:

li $t0, 99

li $t1, 44

loop: addi $t0, $t0, -1

lw $t1, 0($t1)

bne $t0, $zero, loop

add $v0, $t0, $zero

What is the static instruction count of this code? What is the dynamic instruction count? (Assume any pseudoinstructions are counted as 1 instruction).

How many times is the instruction memory accessed? How many times is the data memory (i.e. lw/sw) accessed?

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Answer #1

Answer:-------------

a). Static Instruction Count: 6 (Since there are only 6 instructions in the code.)
Dynamic Instruction Count: (99 * 3) - 1 + 3 = 299 (The two li instructions and the add instruction only executed once.
The loop itself executes 99 times but bne instructions executes only 98 times since at the 99th iteration, $t0 = 0 and bne instruction won't executed.)

b). Instruction Memory Accessed: 299 (Number of times program counter updated)
Data Memory Accessed: 99 (Number of times lw or load instruction was executed)

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