An apple at 30°C with average mass of 0.2 kg and average specific heat of 3.65...
An apple at 30°C with average mass of 0.2 kg and average specific heat of 3.65 kJ/kg °C is in contact with a 0.1 kg cold iron at 10 °C. Determine the final temperature of the apple and the heat transfer between apple and iron. Use appendix to find the specific heat for iron. Neglect change of KE and PE of the system.
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An apple at 30°C with average mass of 0.2 kg and average
specific heat of 3.65...
A 0.1 kg iron horseshoe that is initially at 726◦C is dropped into a bucket containing...
A 0.1 kg iron horseshoe that is initially at 726◦C is dropped into a bucket containing 31 kg of water at 24◦C. What is the final equilibrium temperature? Neglect any energy transfer to or from the surroundings and assume the specific heat of iron is 448 J/kg ·◦ C . The specific heat of water is 4186 J/kg ·◦ C . Answer in units of ◦C.
Tubular heat exchanger design A liquid food (with specific heat 3.9 kJ/[kg °C]) flows in the...
Tubular heat exchanger design A liquid food (with specific heat 3.9 kJ/[kg °C]) flows in the inner pipe of a double pipe heat exchanger. The liquid food enters the heat exchanger at 72°C and exits at 6°C at a flow rate of 0.5 kg/s. In the annular section, cold water at 2°C enters the heat exchanger and flows concurrently at a flow rate of 12 kg/s. The average specific heat of water is 4.10 kJ/(kg °C). Assuming steady-state conditions. a)...
An aluminium object with a mass of 5.77 kg and at a temperature of 23.3 °C...
An aluminium object with a mass of 5.77 kg and at a temperature of 23.3 °C comes to thermal contact with a 9.26 kg copper object which is initially at a temperature of 97.7 °C. What is going to be the equilibrum temperature of the two objects? Neglect heat transfer between the objects and the environment. The specific heats are: cAl = 900 J/kg°C and cCu = 387 J/kg°C.
Problem 2: (10 pts) A 30-kg iron block at initial temperature 200°C and a 40-kg copper...
Problem 2: (10 pts) A 30-kg iron block at initial temperature 200°C and a 40-kg copper block at initial temperature 100°C are dropped into a very large lake at 20°C. Thermal equilibrium is established after a while as a result of heat transfer between the blocks and lake water. Both blocks have constant specific heats, i.e. Ciron = 0.45 kJ/kg. K and Ccopper = 0.386 kJ/kg. K. Hint: The very large lake can be treated as a heat reservoir and...
An aluminum block weighing 32 kg initially at 140°C is brought into contact with a block...
An aluminum block weighing 32 kg initially at 140°C is brought into contact with a block of iron weighing 44 kg at 60°C in an insulated enclosure. Determine the final equilibrium temperature and the total entropy change for this process. The specific heat of aluminum at 400 K is Cp0.949 kJ/kg.K. The specific heat of iron at room temperature is Cp=0.45 kJ/kg.K. The final equilibrium temperature is 108,35 K. The total entropy change for this process is 397 kJ/K
A metal part is undergoing a heat-treating process, it has a mass of 12 kg and...
A metal part is undergoing a heat-treating process, it has a
mass of 12 kg and is initially at 950∘C. The part is quenched in a
tank containing 225 kg of water, initially at 35∘C. Consider the
heat transfer between the tank and its surroundings to be
negligible. Taking the specific heat of the metal part and water as
constant at 0.5 kJ/kg.K and 4.2 kJ/kg.K respectively, determine :
The final equilibrium temperature after quenching Tf= ∘C The amount
of...
2. A 0.825-kg block of iron, with an average specific heat of 5.60 x102 J/kg K,...
2. A 0.825-kg block of iron, with an average specific heat of 5.60 x102 J/kg K, is initially at a temperature of 352°C. It is placed in a calorimeter that has 40.0 g of water at 20.0°C. What is the final thermal equilibrium temperature? If your answer if 100.0°C, calculate the amount of water that remains in liquid form. Treat the mass and heat capacity of the calorimeter as neglible.
my work С 2 10 points An aluminum block weighing 22 kg initially at 140°C is...
my work С 2 10 points An aluminum block weighing 22 kg initially at 140°C is brought into contact with a block of iron weighing 24 kg at 60°C in an insulated enclosure. Determine the final equilibrium temperature and the total entropy change for this process. The specific heat of aluminum at 400 Kis Cp = 0.949 kJ/kg.K. The specific heat of iron at room temperature is Cp = 0.45 kJ/kg.K. 01:56:29 The final equilibrium temperature is K. The total...
A 34 kg iron block and a 48-kg copper block, both initially at 80°C, are dropped...
A 34 kg iron block and a 48-kg copper block, both initially at 80°C, are dropped into a large lake at 15°C. Thermal equilibrium is established after a while as a result of heat transfer between the blocks and the lake water. Determine the total entropy change for this process. The specific heat of Iron at room temperature is cp0.45 kJ/kg.K. The specific heat of copper at 27°C is ep 0,386 kJ/kg.K. Iron Lake 15°C Copper The total entropy change...
An insulated beaker with negligible mass contains liquid water with a mass of 0.325 kg and...
An insulated beaker with negligible mass contains liquid water with a mass of 0.325 kg and a temperature of 77.6 ∘C What is the final temperature of the system if 0.1 kg of ice at a temperature of -12.4 ∘C are dropped into the water? Take the specific heat of liquid water to be 4188 J/kg⋅K , the specific heat of ice to be 2111 J/kg⋅K , and the heat of fusion for water to be 334 kJ/kg . T= ∘C
Problem 2: (10 pts) A 30-kg iron block at initial temperature 200°C and a 40-kg copper block at initial temperature 100°C are dropped into a very large lake at 20°C. Thermal equilibrium is established after a while as a result of heat transfer between the blocks and lake water. Both blocks have constant specific heats, i.e. Ciron = 0.45 kJ/kg. K and Ccopper = 0.386 kJ/kg. K. Hint: The very large lake can be treated as a heat reservoir and...
An aluminum block weighing 32 kg initially at 140°C is brought into contact with a block of iron weighing 44 kg at 60°C in an insulated enclosure. Determine the final equilibrium temperature and the total entropy change for this process. The specific heat of aluminum at 400 K is Cp0.949 kJ/kg.K. The specific heat of iron at room temperature is Cp=0.45 kJ/kg.K. The final equilibrium temperature is 108,35 K. The total entropy change for this process is 397 kJ/K
A metal part is undergoing a heat-treating process, it has a
mass of 12 kg and is initially at 950∘C. The part is quenched in a
tank containing 225 kg of water, initially at 35∘C. Consider the
heat transfer between the tank and its surroundings to be
negligible. Taking the specific heat of the metal part and water as
constant at 0.5 kJ/kg.K and 4.2 kJ/kg.K respectively, determine :
The final equilibrium temperature after quenching Tf= ∘C The amount
of...
2. A 0.825-kg block of iron, with an average specific heat of 5.60 x102 J/kg K, is initially at a temperature of 352°C. It is placed in a calorimeter that has 40.0 g of water at 20.0°C. What is the final thermal equilibrium temperature? If your answer if 100.0°C, calculate the amount of water that remains in liquid form. Treat the mass and heat capacity of the calorimeter as neglible.
my work С 2 10 points An aluminum block weighing 22 kg initially at 140°C is brought into contact with a block of iron weighing 24 kg at 60°C in an insulated enclosure. Determine the final equilibrium temperature and the total entropy change for this process. The specific heat of aluminum at 400 Kis Cp = 0.949 kJ/kg.K. The specific heat of iron at room temperature is Cp = 0.45 kJ/kg.K. 01:56:29 The final equilibrium temperature is K. The total...
A 34 kg iron block and a 48-kg copper block, both initially at 80°C, are dropped into a large lake at 15°C. Thermal equilibrium is established after a while as a result of heat transfer between the blocks and the lake water. Determine the total entropy change for this process. The specific heat of Iron at room temperature is cp0.45 kJ/kg.K. The specific heat of copper at 27°C is ep 0,386 kJ/kg.K. Iron Lake 15°C Copper The total entropy change...
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