When substrate concentration is much less than KM, the rate of catalysis is almost equal to
A) Kd B)Vmax / KM C) kcat D) None of the above E) Vmax
((A-E) are answer choices)
When substrate concentration is much less than KM, the rate of catalysis is almost equal to...
Enzyme activity will be high when substrate concentration is equal to KM b. below KM c. above KM d. none of the above Metalloproteases mostly use the element Cu b. Fe c. Zn d. Mn
only 7-9,11-12
7. When does the KM equal the Kd? 8. The kcat refers to which steps in the catalytic mechanism? 9. The KM refers to which steps in the catalytic mechanism? L0. Calculate the Km, when v = .123 HM/sec, [E]T = 1.0 HM, kcat 720/s and [S 11. Which constant would you use to compare substrate specificities? 12. The upper limit of enzyme catalysis is called...?
7. When does the KM equal the Kd? 8. The kcat refers...
1. According to the Michaelis-Menten equation, when is the reaction velocity at half the maximal value (vo = 0.5 Vmax) A. when [S] = 0.5 Km B. when [S] = 1.0 Km C. when vo = kcat [E] D. when vo = kcat / Km 2. The value of Vmax depends on ... A. k1 and k-1 B. k1 and k2 C. k1 only D. k2 only 3. When is Km approximately equal to Kd? A. when k1 is much...
only 7-9,11-12
7. When does the KM equal the Kd? 8. The kcat refers to which steps in the catalytic mechanism? 9. The KM refers to which steps in the catalytic mechanism? L0. Calculate the Km, when v = .123 HM/sec, [E]T = 1.0 HM, kcat 720/s and [S 11. Which constant would you use to compare substrate specificities? 12. The upper limit of enzyme catalysis is called...?
What is substrate concentration, expressed as a multiple of Km, when an enzyme reaction is observed to have an initial rate Vo = 0.75 Vmax. Select one: O a. [S] = 0.33 x km O b. [S] = 0.25 km O c. [S] = 0.75 x Km O d. [S] = 0.3 x km O e. [S] = 0.5 x km Check Next page ime Jump to...
The relation between Reaction Velocity and Substrate Concentration: Michaelis-Menten Equation a) At what substrate concentration would an enzyme with a kcat of 30.0 s-1 and a Km of 0.0050 M operate at one-quarter of its maximum rate? b) Determine the fraction of Vmax that would be obtained at the following substrate concentrations: [S]=Km/2, [S]=2Km, [S]=10Km
Which of the following statements are corrects? When the substrate concentration is equal to KM, the reaction rate is half of its maximal value The value of KM is proportional to the concentration of the ES complex Inhibitors are molecules capable of decreasing the enzyme activity Uncompetitive inhibitors have no effect on Vmax fill in the blanks The respiratory chain is a set of_______complexes whose role is to transport _______ from reduced co-factors to dioxygen. The (entry from previous blank)...
Enzyme X has a Km for substrate A which is twice as large as its Km for substrate B. If the enzyme is added to a solution containing equal, but low concentrations of A and B and Vmax for A and B are equal: substrate A will be used at a rate equal to substrate B substrate A will be used at a rate greater than substrate substrate B will be used at a rate greater than substrate A. substrate...
For enzymes in which the slowest (rate-limiting) step is the reaction: K2 ES → E+P Km becomes equivalent to: A) kcat. B) the [S] where V0 = Vmax. C) the dissociation constant, Kd, for the ES complex. D) the maximal velocity. E) the turnover number. The answer is C), could you please explain?
19, Which of the following is true? Enrymes force reactions to proceed in only one direction. A) Enrymes alter the equilibrium of the reaction. Enzymes alter the standard free energy of the reaction. All of the answers are correct. None of the answers is correct B) C) D) E) 20). When substrate concentration is much greater than K, the rate of catalysis is almost equal to A) K B) /K C) Vea D) All of the answers are correct. E)...