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Some C6H5CH2OH is allowed to dissociate into C6H5CHO and H2 at 523 K. At equilibrium, [C6H5CH2OH]...

Some C6H5CH2OH is allowed to dissociate into C6H5CHO and H2 at 523 K. At equilibrium, [C6H5CH2OH] = 0.196 M, and [C6H5CHO] = [H2] = 5.04×10-2 M. Additional C6H5CHO is added so that [C6H5CHO]new = 8.59×10-2 M and the system is allowed to once again reach equilibrium. C6H5CH2OH(g) -->C6H5CHO(g) + H2(g) K = 1.30×10-2 at 523 K (a) In which direction will the reaction proceed to reach equilibrium? (b) What are the new concentrations of reactants and products after the system reaches equilibrium?

[C6H5CH2OH] = M

[C6H5CHO] = M

[H2] = M

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