Python Please
Write a recursive function rPatt that, when given a power of 2 as an argument, returns the patterns indicated in the examples.
OutPut:
>>> rPatt(1)
'|'
>>> rPatt(2)
'|--|'
>>> rPatt(4)
'|--|----|--|'
>>> rPatt(8)
'|--|----|--|--------|--|----|--|'
>>> rPatt(16)
'|--|----|--|--------|--|----|--|----------------|--|----|--|--------|--|----|--|'
>>> rPatt(32)
'|--|----|--|--------|--|----|--|----------------|--|----|--|--------|--|----|--|--------------------------------|--|----|--|--------|--|----|--|----------------|--|----|--|--------|--|----|--|'
>>>
def rPatt(n):
if n<=1:
print(end='|')
return
rPatt(int(n/2))
for i in range(n):
print(end='-')
rPatt(int(n/2))
n = int(input("Enter a number in powers of 2:"))
rPatt(n)

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thanks.
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Python Please Write a recursive function rPatt that, when given a power of 2 as an...
(for python)
[27] Write a recursive function to calculate the following for a given input value for x. result = 1+ 2+ 3 ..... + x For example: if the input for x is 5, the result will be 1+2+3+4+5 = 15 if the input for x is 8, the result will be 1+2+3+4+5+6+7+8 = 36 Write recursive function.
python language.
[27] Write a recursive function to calculate the following for a given input value for x. result = 1 + 2 + 3 .... + x For example: if the input for x is 5, the result will be 1+2+3+4+5 = 15 if the input for x is 8, the result will be 1+2+3+4+5+6+7+8 = 36 Write recursive function.
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need help with python ( no loops used please!)
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****python****
Q1.
Write a recursive function that returns the sum of all numbers
up to and including the given value.
This function has to be recursive; you may not use loops!
For example:
Test
Result
print('%d : %d' % (5, sum_up_to(5)))
5 : 15
Q2,
Write a recursive function that counts the number of odd
integers in a given list.
This function has to be recursive; you may not use loops!
For example:
Test
Result
print('%s : %d' % ([2,...
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