If X is a random variable such that E(X)=3 and V(X)=2, and if Y is a random variable such that Y=6+2X. Calculate the mean and variance of Y.
a) E(Y)=12
b) V(Y)=
we want to find V(Y)
given value E(X)=3 V(X)=2
Y=6+2X.
V(Y)=V(6+2*x) = 2^2 * V(x) = 4*2 = 8 ( we know the constant of variance is zero)
If X is a random variable such that E(X)=3 and V(X)=2, and if Y is a...
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can you solve 1 and 2 please???
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