what is the equilibrium temperature when pouring 200 grams at 80 degrees Celsius while at room temperature into a 50 gram brass flask?
specific heat of brass is 380 J/Kg-K
specific heat of water is 4186J/Kg-K
Room temperature is 20oC
Heat gained by brass flask = Heat lost by water
MBCB(T-TB)=MwCw(Tw-T)
0.05*380*(T-20)=0.2*4186*(80-T)
856.2T=67356
T=78.67oC
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