Question

This is in C language. Cannot use any built-in funcitons

1. The program will contain a function with the signature 'double power(double base, double n)'.
2. Your program will call this function in a loop in the main function, computing the first power(2,1) to power(2,10) and print out these results to the terminal.

Answer 1

Program:

#include <stdio.h>

double power(double base, double n); // function proto type

int main() {

double base=2,n=1; // variable declaration

while(n<=10) // Loop runs from 1 to 10

{

printf("%.0lf^%.0lf = %.lf\n", base,n,power(base,n)); // calling function

n++; // increment n value

}

return 0;

}

double power(double base, double n) // Called function

{

double result = 1; // variable declaration

while (n != 0) { // Loop to find the power

result *= base;

n--; // decrement n value

}

return result; // return power

}

Output: