Question

use error propagation to calculate x^2, the error in x^2. L and h both have errors. x^2 is related to L and h in the following way:

x^2=4Lh

(not by using ln)

Answer 1

Hi,

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STEP 1:

Given function,

STEP 2:

Product rule for error propagation:

If, , then error in is given by,

Also, if , then error in is given by,

STEP 3:

Calculating error propagation :

We have,

Hence, applying product rule of errors , we get

Where, , and are errors in , and respectively.

We were asked to find .

STEP 4:

Finding :

Substituting for x,