Question

IN PYTHON

Write a program that, given a set of words in a list, calculate how many words begin with the letter you capture. Entry: 5 words and 1 letter Output: # of words that have the letter.

IMPORTANT NOTE: Your program should not include an input message: you are only going to capture the 5 words and finally the letter you want to find and as an output message you must indicate only the number of words that begin with the letter. IT DOESN'T MATTER IF THE LETTERS ARE GIVEN IN CAPITAL OR lower case.

EXAMPLE

Hola
Mundo
hermoso
Estamos
listos
h

OUTPUT

2

example 2:

cosas
cambios
materia
>unidades
cursos
C

OUTPUT

3

example 3:

cosas
cambios
materia
unidades
cursos
O

Output

0

Example 4:

Entrada
Hola
Mundo
hermoso 
Estamos
listos
e

OUTPUT

1

Answer 1

Here in this Python Program

- Consider a list in the program say list1 which contains some words and a char namely char1 which contains one single char.

- In the for loop, for every word we are taking out the first char of the word and then comparing it with char1

- If it matches we are incrementing the count of a variable namely count(Here we are not considering the case so we are changing both the cases of the characters to upper and comparing it)

- Finally printing the count variable to the console, which contains the count of the number of words starting with that particular character.

Similarly, we are testing with

1. list2 and char2

2. list3 and char3

3. list3 and char3

Program:

list1=['Hola','Mundo','hermoso','Estamos','listos']
list2=['cosas','cambios','materia','>unidades','cursos']
list3=['cosas','cambios','materia','>unidades','cursos']
list4=['Entrada','Hola','Mundo','hermoso','Estamos','listos']
char1='h'
char2='C'
char3='O'
char4='e'
count=0
for i in list1:
if i[0].upper()==char1.upper():
count=count+1

print(count)

Testcase-1:

Test case-2:

Test case-3:

Test case-4:

Hope this Helps!!!

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