From generation to generation, the mean age when smokers first start to smoke varies. However, the standard deviation of that age remains constant at around 2.1 years. A survey of 43 smokers of this generation was done to see if the mean starting age is at least 19. The sample mean was 18.1 with a sample standard deviation of 1.3. Do the data support the claim at the 5% level?
Note: If you are using a Student's t-distribution for the problem, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.)
A. X-bar ~ ______ (__________,______________)
B. What is the test statistic? (If using the z distribution round your answers to two decimal places, and if using the t distribution round your answers to three decimal places.)
C. What is the p-value? (Round your answer to four decimal places.)
D. Sketch a picture of this situation. Label and scale the horizontal axis and shade the region(s) corresponding to the p-value.
E. Indicate the correct decision ("reject" or "do not reject" the null hypothesis), the reason for it, and write an appropriate conclusion.
(i) Alpha (Enter an exact number as an integer, fraction, or
decimal.)
α =
F. Construct a 95% confidence interval for the true mean. Sketch the graph of the situation. Label the point estimate and the lower and upper bounds of the confidence interval. (Round your lower and upper bounds to two decimal places.)
From generation to generation, the mean age when smokers first start to smoke varies. However, the...
The mean age when smokers first start is 13 years old with a population standard deviation of 2 years. A researcher thinks that the smoking age has significantly changed since the invention of ENDS—electronic nicotine delivery systems. A survey of smokers of this generation was done to see if the mean age has changed. The sample of 30 smokers found that their mean starting age was 12.2 years old. Do the data support the claim at the 5% significance level?...
The mean age of De Anza College students in a previous term was 26.6 years old. An instructor thinks the mean age for online students is older than 26.6. She randomly surveys 56 online students and finds that the sample mean the 5% level s 29.8 with a standard deviation of 2.1. Conduct a hypothesis test Note: If you are using a Student's t-distribution for the problem, you may assume that the underlying population is normally distributed. (In general, you...
A particular brand of tires claims that its deluxe tire averages
at least 50,000 miles before it needs to be replaced. From past
studies of this tire, the standard deviation is known to be 8,000.
A survey of owners of that tire design is conducted. Of the 32
tires surveyed, the mean lifespan was 46,600 miles with a standard
deviation of 9,800 miles. Using alpha = 0.05, is the data highly
consistent with the claim?
Note: If you are using...
The mean age when smokers first start is 13 years old with a population standard deviation of 1.9 years. A researcher thinks that smoking age has significantly changed since the invention of ENDS-electronic nicotine delivery systems. A survey of smokers of this generation was done to see if the mean age has changed. The sample of 31 smokers found that their mean starting age was 12.2 years old. Do the data support the claim at the 10% significance level? What are the...
Suppose that students own an average of 4 pairs of jeans. 8 people from your class were surveyed to determine if the average for students in college is higher than 4. DATA TO USE: 3, 4, 4, 5, 5, 5, 7, 12 A) In words, CLEARLY state what your random variable X or P' represents. B) State the distribution to use for the test. If t, include the degrees of freedom. If normal, include the mean and standard deviation. C)...
Problem 2. The data below gives the mean price (in cents) of a litre of regular gasoline at self-service filling stations at a sample of six urban centres in Canada in May 2012. Urban area Halifax Saint John, NB Toronto Thunder Bay Winnipeg Victoria Price/litre 131.5 129.7 128.9 138.2 122.1 131.8 Provide answers to the following to two decimal places. Part (a) Find the sample mean (in cents). Part (b) Find the sample standard deviation (in cents). Part (c) Using...
Based on interviews with 96 SARS patients, researchers found that the mean incubation period was 5 days, with a standard deviation of 15.4 days. Based on this information, construct a 95% confidence interval for the mean incubation period of the SARS virus. Interpret the interval. The lower bound is days. (Round to two decimal places as needed.) The upper bound is days. (Round to two decimal places as needed.) Interpret the interval. Choose the correct answer below. O A. There...
Based on interviews with 62 SARS patients, researchers found that the mean noutation period was 4.3 days, with a standard deviation of 14.9 days. Based on this information, construct a 95% confidence interval for the moon incubation period of the SARS virus. Interpret the interval The lower bound is days. (Round to two decimal places as needed.) The upper bound in days. (Round to two decimal places as needed) Interpret the interval Choose the correct answer below. O A There...
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 64 dates, the mean record high daily temperature in a certain city has a mean of 85.80°F. Assume the population standard deviation is 15.07°F. The 90% confidence interval is (ID). (Round to two decimal places as needed.) The...
You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals From a random sample of 57 dates, the mean record high daily temperature in a certain city has a mean of 83.56°F. Assume the population standard deviation is 14 43°F. The 90% confidence interval is (0) (Round to two decimal places as needed.)...