Question

A parallel-plate capacitor is filled with a dielectric with K = 4. The plate area is 3 m2 and the plate separation is 2 mm. The capacitance of this capacitor is


a) 210 nF.
b) 18 nF.
c) 8 nF.
d) 13 nF.
e) 53 nF.

Answer 1

capacitance C = ε₀ A/r , ε₀ = 8.854x10^-12 , A = 3 m^2 , r = 2 mm = 0.002 , k=4
e) 53 nF.

Answer 2

Given dataDielectric constant, K = 4Area of the plate is, A = 3 m^{2Plate seperation is, d = 2 mm= (2 mm) (10-3 m / 1mm)}= 2 * 10^-3 mSolution:The capciatance of the capacitor is,C= ε₀KA / d= (8.854 * 10^-12 F/m) (4) (3 m²) / (2 * 10^-3 m )= 53.1 * 10^-9 F˜ 53 nFOption (e) is correct

Answer 3

capacitance C = ε₀ A/r , ε₀ = 8.854x10^-12 , A = 3 m^2 , r = 2 mm = 0.002 , k=4
e) 53 nF.

Answer 4

a) 210 nF.

Answer 5

a) 210 nF.