Question

How do you find the initial concentration if you are only given the initial volume and final volume? I have tried using the V(i) x C(i) =V(f) x C(f) equation but it needs at least 3 figures so I'm a bit lost right now.

DILUTION WORKSHEET Solution #1 Concentration = 0.0232 0% Solution in volumetric flask before water is added to the line Solution in volumetric flask after water has been added to the line Diluted Solutions V #3 18.00mL 0.0232% 10 mL-0186 Pierre 400 mL somL 2. 0 #4

Answer 1

Solution #1 - Concentreaction = 0.0232 m. i concentration aree ree preesented in terms or molarcity ore noremality. molarity is defined as the number of moles on solure divided by number of lares a solution. The firest column to table gives: Solusion en volumetric flast before watere as added to the line... So as the solution is not diluted with water ore any changes has been made toto ut, The concentreation reemains same. 80, Diluted solution # 2: - Vi = 8.00 ML i = 0.0232 m molarity = number or moles volume in ltres. 0.02327 8 x 103 moles = no. di moles o no. o mili moles = 0.1856 mil moles

Solusion in volumetric flash after water hos been added to the line. It becomes VF & CF. As number of moles or solution cuatire &s freee from that solute becomes dilute. recomain same as cf charges & molarity a number of moles milimoles volume in tires/mili ltres. 0.1856 ralli moles 10 mixi ltres = 0.01856 m. Diluted solution 3 Similarly, - 5.00 ML (i=0.0232 m number of mili-males Vix ci = 0.0232x 5 = 0.116 mili moles Vea 10mL. molareity a number of mili-moles rol in mila ures - 0.116 mili-moles 10 pali-lires = 0.016m

Diluted solutions #M: Vi = 2 mtr ci = 0.0232 mi numbere di mil moles Nixci a 20.0232 = 0.0064 mil moles NG = 10mL. molarity becomes numbere or mcl.moles volume en mit ihres. a oonby so - 0.00ubym. Solution in volumetric I Solution en volumetric flash beforce watere &s! frass after watere is added. I added Dilured solutions ! Vi VE CE 0.0232m lom 0.01856 m # 5mi 0.0232m 0.0116m # 2 ML 0.09320 lom O DOM GYM, #