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Consider the system shown in the figure. Block A has weight 4.91 N and block B has weight 2.94 N. Once block B is set in...

Consider the system shown in the figure. Block A has weight 4.91 N and block B has weight 2.94 N. Once block B is set into downward motion, it descends at a constant speed. Assume that the mass and friction of the pulley are negligible.

Calculate the coefficient of kinetic friction mu between block A and the table top.

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Answer #1
it descend at constant speed means that the net force is 0

force in B : W_b - T = 0
T = W_b

force in A : T - Ff = 0
T = Ff
W_b = Ff
2.94 = µ * W_a
µ = 2.94 / 4.91
µ = 0.599
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