r = 131 pm ,
for bcc lattice sqrt(3) x a = 4r , ( i.e along body diagonal )
a = 4r/1.732 =2.31 r = 2.31 x131 pm = 302.61 pm
density = z x M/(N x a^3) where z = 2 ( number of atoms per unit cell for bcc),
M = 50.94 for vanadium, N = 6.023 x10^ 23, a = 2.31
d = ( 2 x50.94)/(6.023 x10^ 23 x (302.61)^3 x (10^ -10)^3)
= 6.104 gm/cc
Vanadium crystallizes in a body centered cubic structure and has an atomic radius of 131 pm....
Vanadium crystallizes in an body centered cubic structure and has an atomic radius of 131 pm. Determine the density of vanadium, if the edge length of a bcc structure is 4r/3^1/2 Answer: 6.11 g/cm3
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