the original problem was:Solve: sin(3x)-sin(x)=cos(2x)so far i've gooten to:sin(x)(2sin(x)cos(x)-1)=cos^2(x)-sin^2(x)Where would I go from here?
Dont copié formé thé book oh ya dont copié formé thé book cause you Oiil inde up being triste soi remembré not toi copié frome thé book oh ya!translation in english please!
the original problem was: Solve: sin(3x)-sin(x)=cos(2x) so far i've gotten to: sin(x)(2sin(x)cos(x)-1)=cos^2(x)-sin^2(x) Where would I go from here?
Prove:sin2x / 1 - cos2x = cotxMy Attempt:LS:= 2sinxcosx / - 1 - (1 - 2sin^2x)= 2sinxcosx / - 1 + 2sin^2x= cosx / sinx - 1= cosx / sinx - 1/1= cosx / sinx - sinx / sinx--Prove:2sin(x+y)sin(x-y) = cos2y - cos2xMy Attempt:RS:= 1 - 2sin^2y - 1 - 2sin^2x= 1 - 1 - 2sin^2y - 2sin^2x= -2...
Find sin(x/2) if sin(x)= -0.4 and 3pi/2 < or equal to (x) < or equal to 2piLet's use cos 2A = 1 - 2sin2 A and we can match cos x = 1 - 2sin2 (x/2) so we will need cos x we know sin x = -.4 and x is in the fourth quadrant, so the cosine will be positive. Drawing a right angl...
2) Use the sum and difference identites sin[x + pi/4] + sin[x-pi/4] = -1 sinx cospi/4 + cosxsin pi/4 + sinx cos pi/4 - cosx sin pi/4 = -1 2 sin x cos pi/4 =-1 cos pi/4 = sqr2/2 2sin^x(sqrt2/2) = -1 sin x = -sqrt2 x = 7pi/4 and 5pi/4 Am I correct?
cos(tan + cot) = csconly simplify one side to equal cscso far I got this far: [((cos)(sin))/(cos)] + [((cos)(cos))/(sin)] = cscI don't know what to do next
the original problem was: (sin x + cos x)^2 + (sin x - cos x)^2 = 2steps too pleaseI got 1 for (sin x + cos x)^2 but then what does (sin x - cos x)^2 become since it's minus?
Solve the following equation for 0 less than and/or equal to "x" less than and/or equal to 360--cos^2x - 1 = sin^2x--Attempt:cos^2x - 1 - sin^2x = 0cos^2x - 1 - (1 - cos^2x) = 0cos^2x - 1 - 1 + cos^2x = 02cos^2x - 2 = 0(2cos^2x/2)= (-2/2)cos^2x = -1cosx = square root of -1And I c...
Let g(x) = sin (cos x^3) Find g ' (x):The choices are a) -3x^2sinx^3cos(cos x^3)b) -3x^2sinx^3sin(cos x^3)c) -3x^2cosx^3sin(cos x^3)d) 3x^2sin^2(cos x^3)I'm not exactly sure where I should start.Should I begin with d/dx of sin? Or do the inside derivative first...and do I have t...
find all solutions in the interval [0,2 pi) sin(x+(3.14/3) + sin(x- 3.14/3) =1 sin^4 x cos^2 xSince sin (a+b) = sina cosb + cosb sina and sin (a-b) = sina cosb - cosb sina, the first problem can be written 2 sin x cos (pi/3)= sin x The solution to sin x = 1 is x = pi/2 For your o...
Prove each identity:a) 1-cos^2x=tan^2xcos^2xb) cos^2x + 2sin^2x-1 = sin^2xI also tried a question on my own:tan^2x = (1 – cos^2x)/cos^2xR.S.= sin^2x/cos^2x I know that the Pythagorean for that is sin^2x + cos^2x That's all I could do.