what is the derivative of x/tan(x) and find f'(pi/4) f'(x)=(tanx-x*sec(x)^2)/(tanx)^2 That's the quotient rule for derivatives or as my teacher says: Low,low, low D'High, minus High d'low all over low square that's the quotient rule. It's a song which helps. D'High or d'low...
Dont copié formé thé book oh ya dont copié formé thé book cause you Oiil inde up being triste soi remembré not toi copié frome thé book oh ya!translation in english please!
If α and β are two angles in Quadrant II such that tan α= -1/2 and tan β = -2/3, find cos(α+β)Work:cos(α+β) = [ 1 - (tan α)(tan β) ] / [ 1 + (tan α)(tan β)]cos(α+β) = [ 1 - (-1/2)(-2/3) ] / [ 1 + (-1/2)(-2/3)]c...
2 times the square root of x minus 1 minus the square root of 3x minus 5 equals the square root of x minus 9
Simplify 1 over 2 of 1 over 4 devide 1 over 3 all over 1 over 6 minus 3 over 4 plus 1 over 2
how doessecx(tanx + tan^2x- sec^2x)simplified tosec x (tanx -1)?
what is the quotient of y minus 5 times the square root of 2y square minus 7y minus 15?
2^2x-1 = 32^x-22/x - 1/2x= 1/2 (2 over x minus 1 over 2x equals 1 over 2)3/x + 8/x-5= 1(3 over x plus 8 over x minus 5 equals 1)
(1/sec 0 + tan 0) + (1/ sec 0 - tan 0 )= 2 sec 0
How would you establish this identity: (1+sec(beta))/(sec(beta))=(sin^2(beta))/(1-cos(beta))on the right, sin^2 = 1-cos^2, that factor to 1-cos * `1+cos, then the denominator makes the entire right side 1+cosB which is 1+1/sec which is 1/sec (sec+1) qedusing sec(beta) = 1/cos(bet...
1. (sec^2x-6tanx+7/sec^2x-5)=(tanx-4/tanx+2)2. (sin^3A+cos^3A/sinA+cosA)=1-sinAcosA3. csc^6x-cot^6x+1+3csc^2xcot^2xplease help
Simplify this complex rational expression: 8 divided by x square minus 4x minus 21 minus 1 divided by x+3 then all of the above divided by 1 divided by x-7 plus 1 thank you :)