It’s review question, I need this as soon as possible. Thank you 3) For thè diferential equation: (a) The point zo =-1 is an ordinary point. Compute the recursion formula for the coefficients of the power series solution centered at zo- -1 and use it to compute the first th...
the original problem was: (sin x + cos x)^2 + (sin x - cos x)^2 = 2steps too pleaseI got 1 for (sin x + cos x)^2 but then what does (sin x - cos x)^2 become since it's minus?
Dont copié formé thé book oh ya dont copié formé thé book cause you Oiil inde up being triste soi remembré not toi copié frome thé book oh ya!translation in english please!
GOT A 102 ON FACS SPELLING TEST GOT 100 ON FACS TEST GOT A 94 ON MATH TEST GOT 80 ON MATH NTBK QUIZ GOT 100 ON ENG POSTER GOT 87 ON SCI HW GOT A CHECK ON SCI HW/CW GOT A 93 AEVRAGE FOR SSGOT A 87 AVERAHE FOR SCI (for the 2nd quarter 1st quarter i got a 80 so i done some rlly grea...
find all solutions in the interval [0,2 pi) sin(x+(3.14/3) + sin(x- 3.14/3) =1 sin^4 x cos^2 xSince sin (a+b) = sina cosb + cosb sina and sin (a-b) = sina cosb - cosb sina, the first problem can be written 2 sin x cos (pi/3)= sin x The solution to sin x = 1 is x = pi/2 For your o...
Can you check my answers:2) 5/8 - 1/4i got: 3/84) 1 1/2 - 2 4/5i got: 7/106) 5 7/8 + 3 5/12i got: 9 7/2410) 3 1/2 + 2 2/5i got: 5 9/1018) 6 7/12 + 4 5/12i got: 1120) 7 9/10 + 3 3/10i got: 11 1/522) 18 3/8 + 11 6/7i got: 30 13/5624) 26 9/10 + 72 5/6i got: 99 1...
2 times the square root of x minus 1 minus the square root of 3x minus 5 equals the square root of x minus 9
2. A dragon is flying around in a pattern given by the parametric curve r(t) (cos(t) cos((sin(t) sin(t) cos(t)j. cos(t) - cos sin(t)-sin(t) cos(t))j (a) Find a formula for the velocity of the dragon at time t (b) Find all the times at which the dragon's speed is zero. Explai...
The only ideas that can be used include: area ABCI-RA2(A+B+C-lpi), the Pythagorean theorem: Cos c cos a cos b. Vectors-dot product cross product, sin A-sin a/sin c; cos A-cos a sin b/sin c; spherical law of sines, spherical law of cosines for sides and spherical law of cosin...
log(square root of 1-x) - log(square root of x+2)=logx First I sqared both sides and got log 1-x -log x+2=log x squared then i performed the quotient property of logs and got log(1-x/x+2)=log x squared then I got 1-x =x squared (x-2) then I got X cubed - 2x+ x-1=0
the original problem was:Solve: sin(3x)-sin(x)=cos(2x)so far i've gooten to:sin(x)(2sin(x)cos(x)-1)=cos^2(x)-sin^2(x)Where would I go from here?
the original problem was: Solve: sin(3x)-sin(x)=cos(2x) so far i've gotten to: sin(x)(2sin(x)cos(x)-1)=cos^2(x)-sin^2(x) Where would I go from here?