Proving identity(sinx+tanx)/(cosx+1)=tanxRS: (sinx+(sinx/cosx))/(cosx+1)((sinxcosx/cosx)+(sinx/cosx))x 1/(cosx+1)sinx(cosx+1)/cosx x 1/(cosx+1)sinx/cosx = tanxRS = LSHow did sinxcosx/cosx turn to sinx(cosx+1)?
what would be the anser to this question: find x is greater than or equal to zero and y is greater than or equal to zero such that x + y is less than or equal to 10 and 5x +2y is greater than or equal to 20 and 2y is greater than or equal to x and x +...
Graph this:y greater than or equal to 2x-32x-2y is less than or equal to 12x-2y is less than or equal to 12x is less than or equal 2yx is less than or equal yhow do u graph this? how to graph x is less than or equal to y?
sketch the feasible region for this system of the inqualities and find the coordinates of each vertex:y greater than or equal to 1;x less than or equal to 2; -1x+2y less than or equal to 6;1x+2y greater than or equal to 2
9x+5greater than or equal to -40 or 7x+3greater than or equal to -11 solve and graph I got the answer of x greater than or equal -5 or x is greater than or equal to -2 as the solution to this equations, but how do i put this into a soltuion set the way that they want it set up...
Select the point which is in the feasible region of the system of inequalities 4x+y is greater than or equal to 8 2x+5y is greater than or equal to 18 x is less than or equal to 0, y is less than or equal to 0
Solve the following equation for 0 less than and/or equal to "x" less than and/or equal to 360--cos^2x - 1 = sin^2x--Attempt:cos^2x - 1 - sin^2x = 0cos^2x - 1 - (1 - cos^2x) = 0cos^2x - 1 - 1 + cos^2x = 02cos^2x - 2 = 0(2cos^2x/2)= (-2/2)cos^2x = -1cosx = square root of -1And I can't do anything...
For 2cos^2X + cosX - 1= 0 find X 0<X<360 <=greater than or equal to.
tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx(sinx+1)/cosx =2cosxmultiplying both sides by cosxsinx + 1 =2cos^2xsinx+1 = 2(1-sin^2x)2sin^2x + sinx-1=0(2sinx+1)(sinx-1)=0x=30 x=270but if i plug 270 back into the original equation i get undefined because tan 270 is undefined where did i go wrong?
If two sides of a triangle have lengths 4 and 9, then the length of the third side may be any number a) less than 13 b) greater than 5 but less than 13 c) greater than 4 but less than 9 d) greater than 5 I suggest you draw this. It is not d, nor a.it is b. Am...
How many solutions does the equation cosx + 1/2 = 1 have for 0<x<2picosx+1/2=1cosx+1=2cosx=2-1cosx=1therefore 1 solution?A) 1b) 2c) 3d) 4
Can someone help me please5-2x is greater than or equal 7 I get x can be greater than or equal to -1Or x can be less than or equal to 6 And to graph i puta closed dot on -1 and 6 but it keeps saying im wrong i dont understand how im wrong, can someone explain why please thank...
Solve each equation for 0 is less than and equal to "x" is less than and equal to 3603sinx = 2cos^{2}x-----I don't know how to solve this equation...this is what I have, but I don't know if I'm on the right track or not3sinx = 1 - 2sin^{2}x3sinx - 1 + 2sin^{2}x = 02sin^{2}x + 3sinx - 1 = 0sinx(3...
if high count is greater thank 8, medium count greater than 4 less than or equal to 8, and low is less than or equal to 4 write an inequality to find the range at which the count is not medium
Let sin alpha = 5/13 where 90° is less than or equal to alpha is less than or equal to 180° and cos beta = -24/25 where 180° is less than or equal to beta is less than or equal to 270° Find cos (alpha - beta) and tan (alpha + beta)
would this be true53 > 18 - 7x greater or equal to 25subtract 1835 > -7x greater or equal to 7divide by 75 > -x greater or equal to 1
If a+b is less than c+d, and d+e is less than a+b than e is (1)less than c (3)less than d(2)equal to c (4)greater than d
Find the value of x in the interval 0 is less than or equal to x and 360 is greater than or equal to x which satisfies the equation cos x - 2 cos x sin x.
identity: tan2a+sin2a/2cos^2a= =2sinacosa/2cos^2a =2sina+sqr1-cos^2a/2cos^2a =???? ans: 1. sin1+cos2a 2. tan2a 3. cos^2a-sin^2a 4. cot2a 5. 0