find all solutions in the interval [0,2 pi) sin(x+(3.14/3) + sin(x- 3.14/3) =1 sin^4 x cos^2 xSince sin (a+b) = sina cosb + cosb sina and sin (a-b) = sina cosb - cosb sina, the first problem can be written 2 sin x cos (pi/3)= sin x The solution to sin x = 1 is x = pi/2 For your o...
In any angle ABC prove tht the perimeter = a/Sin A(Sin A + Sin B + Sin C)Start with perimeter = a+b+c but b= aSinB/sinA and c= aSinC/SinA and if you dont remember, a=a=a*SinA/ SinA
Dont copié formé thé book oh ya dont copié formé thé book cause you Oiil inde up being triste soi remembré not toi copié frome thé book oh ya!translation in english please!
How would you establish this identity: (1+sec(beta))/(sec(beta))=(sin^2(beta))/(1-cos(beta))on the right, sin^2 = 1-cos^2, that factor to 1-cos * `1+cos, then the denominator makes the entire right side 1+cosB which is 1+1/sec which is 1/sec (sec+1) qedusing sec(beta) = 1/cos(bet...
Solve the following equation for 0 less than and/or equal to "x" less than and/or equal to 360--cos^2x - 1 = sin^2x--Attempt:cos^2x - 1 - sin^2x = 0cos^2x - 1 - (1 - cos^2x) = 0cos^2x - 1 - 1 + cos^2x = 02cos^2x - 2 = 0(2cos^2x/2)= (-2/2)cos^2x = -1cosx = square root of -1And I c...
the original problem was: (sin x + cos x)^2 + (sin x - cos x)^2 = 2steps too pleaseI got 1 for (sin x + cos x)^2 but then what does (sin x - cos x)^2 become since it's minus?
1) 1+cos(3t)/ sin(3t) + sin(3t)/( 1+ cos(3t))= 2csc(3t)2) sec^2 2u-1/ sec^2 2u= sin^2 2u3) cosB/1- sinB= secB+ tanB
The identity of: sin^4x+cos^4x= (sin^2x+cos^2x)(sin^2x+cos^2x) sin^2x+cos^2=1 This is the answer I come up with, it is not one of the options available as an answer. The answers given are 1. -2sin^2xcos^2x 2. 1+2sin^2x-2sin^4x 3. 1+3sin^3x-2sin^2x 4. 1-2sin^2x+2sin^4x 5. 0
cos(tan + cot) = csconly simplify one side to equal cscso far I got this far: [((cos)(sin))/(cos)] + [((cos)(cos))/(sin)] = cscI don't know what to do next
2) Use the sum and difference identites sin[x + pi/4] + sin[x-pi/4] = -1 sinx cospi/4 + cosxsin pi/4 + sinx cos pi/4 - cosx sin pi/4 = -1 2 sin x cos pi/4 =-1 cos pi/4 = sqr2/2 2sin^x(sqrt2/2) = -1 sin x = -sqrt2 x = 7pi/4 and 5pi/4 Am I correct?
prove that sinA/(1+cosA) + (1+cosA)/(sinA) = 2cosecA
Let g(x) = sin (cos x^3) Find g ' (x):The choices are a) -3x^2sinx^3cos(cos x^3)b) -3x^2sinx^3sin(cos x^3)c) -3x^2cosx^3sin(cos x^3)d) 3x^2sin^2(cos x^3)I'm not exactly sure where I should start.Should I begin with d/dx of sin? Or do the inside derivative first...and do I have t...