# find all solutions in the interval [0,2 pi) sin(x+(3.14/3) + sin(x- 3.14/3) =1 sin^4 x cos^2 x Since sin (a+b) = sina cosb + cosb sina and sin (a-b) = sina cosb - cosb sina, the first problem can be written 2 sin x cos (pi/3)= sin x The soluti related homework questions

• #### find all solutions in the interval [0,2 pi) sin(x+(3.14/3) + sin(x- 3.14/3) =1 sin^4 x cos^2 x Since sin (a+b) = sina cosb + cosb sina and sin (a-b) = sina cosb - cosb sina, the first problem can be written 2 sin x cos (pi/3)= sin x The soluti

find all solutions in the interval [0,2 pi) sin(x+(3.14/3) + sin(x- 3.14/3) =1 sin^4 x cos^2 xSince sin (a+b) = sina cosb + cosb sina and sin (a-b) = sina cosb - cosb sina, the first problem can be written 2 sin x cos (pi/3)= sin x The solution to sin x = 1 is x = pi/2 For your...

• #### It’s review question, I need this as soon as possible. Thank you 3) For thè diferential equation: (a) The point zo =-1 is an ordinary point. Compute the recursion formula for the coefficients of...

It’s review question, I need this as soon as possible. Thank you 3) For thè diferential equation: (a) The point zo =-1 is an ordinary point. Compute the recursion formula for the coefficients of the power series solution centered at zo- -1 and use it to compute the first three nonzero terms of the power series when -1)-s and v(-1)-0....

• #### Dont copié formé thé book oh ya dont copié formé thé book cause you Oiil inde up being triste soi remembré not toi copié frome thé book oh ya

Dont copié formé thé book oh ya dont copié formé thé book cause you Oiil inde up being triste soi remembré not toi copié frome thé book oh ya!translation in english please!

• #### In any angle ABC prove tht the perimeter = a/Sin A(Sin A + Sin B + Sin C) Start with perimeter = a+b+c but b= aSinB/sinA and c= aSinC/SinA and if you dont remember, a=a=a*SinA/ SinA

In any angle ABC prove tht the perimeter = a/Sin A(Sin A + Sin B + Sin C)Start with perimeter = a+b+c but b= aSinB/sinA and c= aSinC/SinA and if you dont remember, a=a=a*SinA/ SinA

• #### DSuppose \$39oo is deposited in a savings account that increases exponentially.Detamine thě APv if the acount...

DSuppose \$39oo is deposited in a savings account that increases exponentially.Detamine thě APv if the acount increases to \$t020 in 4 years. Ass ume tne interest Vale remains Constant and no additional deposits or Withdrawals are made. (a.) Let pbe the APY. Note tnat if tme inital balaqe is yo, ne year later tne balane is %more. P- 3 (Tpe...

• #### How would you establish this identity: (1+sec(beta))/(sec(beta))=(sin^2(beta))/(1-cos(beta)) on the right, sin^2 = 1-cos^2, that factor to 1-cos * `1+cos, then the denominator makes the entire right side 1+cosB which is 1+1/sec which is 1/sec (sec+1)

How would you establish this identity: (1+sec(beta))/(sec(beta))=(sin^2(beta))/(1-cos(beta))on the right, sin^2 = 1-cos^2, that factor to 1-cos * `1+cos, then the denominator makes the entire right side 1+cosB which is 1+1/sec which is 1/sec (sec+1) qedusing sec(beta) = 1/cos(beta): 1+sec(beta))/(sec(beta))= 1 + cos(beta) sin^2(beta)/(1-cos(beta)) = (1-cos^2(beta))/(1-cos(beta)) = 1 + cos(beta) This follows e.g. from: (1 - x^2) = (1 - x)(1...

• #### the original problem was: (sin x + cos x)^2 + (sin x - cos x)^2 = 2 steps too please I got 1 for (sin x + cos x)^2 but then what does (sin x - cos x)^2 become since it's minus

the original problem was: (sin x + cos x)^2 + (sin x - cos x)^2 = 2steps too pleaseI got 1 for (sin x + cos x)^2 but then what does (sin x - cos x)^2 become since it's minus?

• #### 2. A dragon is flying around in a pattern given by the parametric curve r(t) (cos(t) cos((sin(t) sin(t) cos(t)j. cos(t) - cos sin(t)-sin(t) cos(t))j (a) Find a formula for the velocity of the dragon...

2. A dragon is flying around in a pattern given by the parametric curve r(t) (cos(t) cos((sin(t) sin(t) cos(t)j. cos(t) - cos sin(t)-sin(t) cos(t))j (a) Find a formula for the velocity of the dragon at time t (b) Find all the times at which the dragon's speed is zero. Explain your reasoning. c) Does the path of the dragon contain...

• #### Solve the following equation for 0 less than and/or equal to "x" less than and/or equal to 360 -- cos^2x - 1 = sin^2x -- Attempt: cos^2x - 1 - sin^2x = 0 cos^2x - 1 - (1 - cos^2x) = 0 cos^2x - 1 - 1 + cos^2x = 0 2cos^2x - 2 = 0 (2cos^2x/2)= (-2/2) cos^

Solve the following equation for 0 less than and/or equal to "x" less than and/or equal to 360--cos^2x - 1 = sin^2x--Attempt:cos^2x - 1 - sin^2x = 0cos^2x - 1 - (1 - cos^2x) = 0cos^2x - 1 - 1 + cos^2x = 02cos^2x - 2 = 0(2cos^2x/2)= (-2/2)cos^2x = -1cosx = square root of -1And I can't do anything...

• #### The only ideas that can be used include: area ABCI-RA2(A+B+C-lpi), the Pythagorean theorem: Cos c cos a cos b. Vectors-dot product cross product, sin A-sin a/sin c; cos A-cos a sin b/sin c; spher...

The only ideas that can be used include: area ABCI-RA2(A+B+C-lpi), the Pythagorean theorem: Cos c cos a cos b. Vectors-dot product cross product, sin A-sin a/sin c; cos A-cos a sin b/sin c; spherical law of sines, spherical law of cosines for sides and spherical law of cosines for angles Let r be the radius of the incircle of triangle...

• #### 1) 1+cos(3t)/ sin(3t) + sin(3t)/( 1+ cos(3t))= 2csc(3t) 2) sec^2 2u-1/ sec^2 2u= sin^2 2u 3) cosB/1- sinB= secB+ tanB

1) 1+cos(3t)/ sin(3t) + sin(3t)/( 1+ cos(3t))= 2csc(3t)2) sec^2 2u-1/ sec^2 2u= sin^2 2u3) cosB/1- sinB= secB+ tanB

• #### Use a double-angle or half-angle formula to simplify the given expressions: 1. If cos^2(39degrees)-sin^2(39degrees) = cosA then what does A equal? 2. If cos^2(3x)-sin^2(3x) = cosB, what does B equal?

I'm just beginning to learn about the double and half angle formulas. However, with these I don't know where to begin. For A it looks like I'm supposed to be using... Sin^2x=(1-cos^2x)/2 and cos^2x=(1+cos2x)/2 and then subtract those two results from one another? I'm confused on how to get rid of 39 degrees. What angles would I be adding or...

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