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Question:how do you factor y^4-1 completely
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how do you factor y^4-1 completely
how do you factor y^4-1 completely?
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Answer #1
first, it is a difference of two squares:
(y^2-1)(y^2+1)
Next, the first term is again the difference of two squares. If you allow imaginary numbers, then the second term is a difference of two squares (y+i)(y-i)
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Answer #2
you should recognize the difference of squares
y^4-1
= (y^2 + 1)(y^2 - 1) , ahh, once more
= (y^2 + 1)(y + 1)(y-1)
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