Question:The identity of:
sin^4x+cos^4x=
(sin^2x+cos^2x)(sin^2x+cos^2x)
sin^2x+cos^2=1
This is the answer I come up with, it is not one of the options available as an answer
The identity of:
sin^4x+cos^4x=
(sin^2x+cos^2x)(sin^2x+cos^2x)
sin^2x+cos^2=1
This is the answer I come up with, it is not one of the options available as an answer
The identity of:
sin^4x+cos^4x=
(sin^2x+cos^2x)(sin^2x+cos^2x)
sin^2x+cos^2=1
This is the answer I come up with, it is not one of the options available as an answer.
The answers given are
1. -2sin^2xcos^2x
2. 1+2sin^2x-2sin^4x
3. 1+3sin^3x-2sin^2x
4. 1-2sin^2x+2sin^4x
5. 0
The identity of:
sin^4x+cos^4x=
(sin^2x+cos^2x)(sin^2x+cos^2x)
sin^2x+cos^2=1
This is the answer I come up with, it is not one of the options available as an answer