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How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that is 80% alcohol to get a solution that is 60% alcohol

How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that is 80% alcohol to get a solution that is 60% alcohol?
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Let x = additive volume in liters . .40*x + .80*10 = .60*(10+x) . .4x +8 = 6 + .6x . 2=.2x . 10=x . check .4*10 +.8*10 = .6 *(10+10)=12,,,,ok .
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How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that is 80% alcohol to get a solution that is 60% alcohol
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