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prove these identies sin^2+tan^2=sec^2-cos^2 sin^2 sec^2 +sin^2=tan^2+sin^2

prove these identies

sin^2+tan^2=sec^2-cos^2

sin^2 sec^2 +sin^2=tan^2+sin^2

Your equations contain only trig operators but they have no arguments
e.g. sin^2 is meaningless, it has to be something like sin^2Ø or sin^2x
Your expression is as meaningless as trying to evaluate
5 + √

anyway .....

for sin^2+tan^2=sec^2-cos^2
LS = sin^2x + sin^2x/cos^2x
= (sin^2x cos^2x + sin^2x)/cos^2x
= sin^2x(cos^2x + 1)/cos^2x
= (1 - cos^2x)(1+cos^2x)/cos^2x
= (1 - cos^4x)/cos^2x

RS = 1/cos^2x - cos^2x
= (1 - cos^4 x)/cos^2x
= LS

the 2nd:

LS = sin^2x(1/cos^2x) + sin^2x
= tan^2x + sin^2x
= RS
Add Answer of: prove these identies sin^2+tan^2=sec^2-cos^2 sin^2 sec^2 +sin^2=tan^2+sin^2
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