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Please write the answers clear and easy to be read and please sipirt the answers so It would be in order

Researchers combined the results from three experiments to investigate whether chest compression only (CC) would improve a he

a) [2 pts] Calculate the null standard error for the difference in sample proportions. Round your answer to three decimal pla

Which of the following is the best interpretation of the null standard error for the difference in sample proportions? (Let A

Which of the following gives the correct formula for calculating standard error of the difference in sample proportions, if y

What is the appropriate conclusion with scope of inference for these data? There is strong evidence to conclude that CC instr

Please write the answers clear and easy to be read and please sipirt the answers so It would be in order
Researchers combined the results from three experiments to investigate whether chest compression only (CC) would improve a heart attack victim's chance of survival compared to standard cardiopulmonary resuscitation (CPR). In each experiment, the emergency services dispatcher randomly assigned either the CC or CPR instructions to a bystander who was at a site where a person had just experienced a heart attack. The results are organized in the table below: CPR 178 1353 1531 Survived? Yes 211 1289 1500 Total 389 2642 3031
a) [2 pts] Calculate the null standard error for the difference in sample proportions. Round your answer to three decimal places. b) [2 pts] Use part (a) to calculate the standardized statistic for these data. Round your answer to three decimal places.
Which of the following is the best interpretation of the null standard error for the difference in sample proportions? (Let A represent the null standard error you calculated in part (a) of the previous problem.) The likelihood of seeing the CC survival rate be at least as much higher than the CPR survival rate as was seen in our sample, assuming the probability of surviving a heart attack is the same regardless of instruction method, is A The chance of surviving a heart attack when the bystander is instructed in CC is (A- 1)*100% higher than when the bystander was told to use CPR. The distance between O and each difference in sample survival rate between those instructed in CC and those instructed in CPR which assumes there is no difference is A, on average The observed difference in sample proportion of heart attack victims who survived between those instructed in CC and those instructed in CPR is A above O.
Which of the following gives the correct formula for calculating standard error of the difference in sample proportions, if you do NOT assume the true proportions are equal. 178 1531 178 1531 1500 1500ー+ 1500 1531 0.5 × (1-0.5) × (1500 + TS31) 389 (1-3031 389 (-) 3031 1500 1531 178 1353 178 1353 211 1289 1289 1353
What is the appropriate conclusion with scope of inference for these data? There is strong evidence to conclude that CC instructions is associated with a higher survival probability than CPR instructions among the heart attack victims in this sample and those similar to them. There is strong evidence to conclude that CC instructions caused a higher survival probability than CPR instructions among the heart attack victims in this sample and those similar to them. There is strong evidence to conclude that CC instructions caused a higher survival probability than CPR instructions among all heart attack victims. There is strong evidence to conclude that CC instructions is associated with a higher survival probability than CPR instructions among all heart attack victims.
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Given to lauslande CPR 趴1 a89 1500 3 89 RGu 303 NO 35 3 Total 153 531 8 153 o-obu 20383

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