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The shaft in the figure below is supported on journal bearings that do not offer any resistance t...

The shaft in the figure below is supported on journal bearings that do not offer any resistance to axial load. The yield stre

The shaft in the figure below is supported on journal bearings that do not offer any resistance to axial load. The yield strength of the material is Ơ,-300 MPa and the safety factor is FS-2.5 1) 2) 3) 4) Determine the reaction at the supports. Draw the shear force, bending and torsion moment diagrams Derive an expression for the components of the stress tensor at a cross section of the shaft Neglect the shear stress due to the transverse shear forces and determine to the nearest millimeter, the smallest diameter of the shaft that will support the loading strength. Maximum Shear Stress Theory (MSST) Distortion Energy Theory (DET) a. b. 30P 250 CA30 150 N 100 mm 100-N 50皿 SON 250 zR
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SOLUTION Given: To design shagt 300 Ma FS 2.5 Gy = 300 MPa FS = 2.5 The belt is inclind in both pulleys Firsty, we have to caNow, horizontal ng diegpom (HLD) RAH +173.21-303-11 +RBH → 17 3.21 x 250-303., 750 + RBH X1000 RBH 184.03 N Gon (i); drauw iNoW こ300MPa FSこ2-5 (a) Maximum shear Sbress theony (MSST) may _ 으 의 °es.309 : 60HN FS 2.5 Let d be diameto of shaft 16(Te) =

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