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For the relation R(O,P,X,Y,E, S) FDs={ O->P, XY->O, OE->S, EY->X, PY->X}. 1.Classi...

for the relation R(O,P,X,Y,E, S) FDs={ O->P, XY->O, OE->S, EY->X, PY->X}. 1.Classify each functional dependency 2. Decompose the relation into BCNF relation. 3. Determine whether each of the decompositions has the lossless join property with respect to F and conclude for the whole decomposition. 4. Determine whether each of the decompositions has the dependency preserving property with respect to FD and conclude for the whole decomposition

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Dear student, according to the question, the solution is as follows:

olutou is as lows: Atktbule FDs乡 we need iden the ona Caudidale ve eliminalín, lho Yedundanc ncy ons t sali the INF Condition

2 NF . The nelolion kuouldl be in INF and PFD PF D PFD Now, Conside시 lke Violaltry Fps and Courtle O, E, s Not resuire d tho

Klus in Ey is the ke bepest even after Co, detonpositionto 2NF enue 4

PD Stalin Nonkat Non No Tra、nitive de づ(E in 3NF go, con s.cdex violativ1 Fps. 0→1) , couru Ati v D-ラ

Prcadure to ve he BCNE The vtlolion shouls be 3NFans its in BONF i Alowra in 3NF out 23 ( P xy is Common Attsibue a Loslem on

So, finally, the relation R (O,P,X,Y,E,S) has been decomposed into 5 relations to meet the requirements of BCNF.

R1(EYX), R2(XYO), R3(OP), R4(PYX), R5(OES)

Thank you, All the best.

If at all any doubts, feel free to contact through the comment section

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