After t hours
The position of Ship A will be (20 + 25*t, 0)
The position of Ship B will be (0, 23*t)
Hence, the distance between the two ships at any time t will be
Taking the derivative of the s function with respect to t, we get
Substituting the value of t=6, since time difference between 6 pm and 12 noon is equal to 6
Hence the distance is changing wrt time at the rate of 33.90 knots when time is equivalent to 6 hours
Note - Post any doubts/queries in comments section.
Due Sun 05/26/2019 11:59 pm Show Intro/Instnactios At noon, ship A is 20 nautical miles due west of ship B. Ship A...