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The line of action of force F passes through point B. Find the moment due to force F about axis AC, given:   F̄ = <1...

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The line of action of force F passes through point B. Find the moment due to force F about axis AC, given:
   = <10, 70, -10> lbs,   AX = 6 ft,   AY = 3 ft,   AZ = 7 ft,   BX = 7 ft,   BY= 5 ft,   BZ = 9 ft,   CX = 5 ft,   CY = 5 ft,   CZ = 1 ft

MAC =      lb·ft

AC= <   ,   ,   >  lb·ft

3 ーF 1

Find the moment about points A, B, C, D, and E, due to force F, given:

  F = 50 lbs,   L1 = 6 ft,   L2 = 7 ft,   L3 = 4 ft

MA =   lb·ft
  MB =   lb·ft
  MC =   lb·ft
  MD =   lb·ft
  ME =   lb·ft


3 ーF 1
0 0
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Thus, the unit vector u along the aris Ac is given as 1, 2,-6 1, 2,6 Substitute, B,-7, By=5, B2-3 F 10, 0, -10 so, 10刊-10 10 2O8 -6 80-x-〈-1, 2, -6 80 41 41 30 and, MAC -80く1,-2,6 〉 [lbs. ft] So, MAc VT1 (b) MAFL 50x6 300 bSince. the points and the force is planar, therefor, moment isbout point is given simply by is the perpendicular From the poi

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