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Determine the molar solubility of AgI in pure water. Ksp (AgI)= 8.51 x 10-17

Determine the molar solubility of AgI in pure water.


Ksp (AgI)= 8.51 x 10-17

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ReportAnswer #1

Ksp=x^2=8.51 x 10^-17

So x=9.22 x 10^-9 M

ReportAnswer #2

s^2=8.51*10^-17

So

s=9.225*10^-9 is the molar solubility

ReportAnswer #3

let s be the solubility... so s and s dissociates...

=> s^2 = 8.51*10^-17 => s = 9.22*10^-9 M

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