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A basketball is dribbled down a basketball court by Cephan Sturry at a velocity of 2.00 m/s. At the moment it is shot to...

A basketball is dribbled down a basketball court by Cephan Sturry at a velocity of 2.00 m/s. At the moment it is shot towards the hoop, the player is 7.24m from the hoop, and that hoop is 3.00m from the ground. The angle between the ball and the hoop is 65o when it is shot. If the basketball rotates from the moment of release until it reaches the hoop at 2 rotations per second, how many rotations will have been made until the ball reaches the hoop?

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The statement is not clear. What is the meaning of angle between the ball and hoop? They probably mean the angle between the line joining the hoop to launch point and the velocity vector of ball. Then the total launch angle would be

3 0 65tan 87.5 7.24

Total time to reach the hoop

7.24 t v cos e

No.of rotations in this time,

7.24 N = v cos e X w

7.24 N = 2 cos 87,5 166 Complete rotations x 2

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