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Given the spectra determine the Molecule formula and structure Analyst Analyst Friday, 5 April 2019 5:14 PM Date 99 98-...

Given the spectra determine the Molecule formula and structure

Analyst Analyst Friday, 5 April 2019 5:14 PM Date 99 98- 96- 94- 479.98cm-1 591.29cm- 92- 1067.08erh- 542.08cm-1 90- 97222c0Carboxylic acid 1С CDCI, a0 220 200 130 110 10 230 10 170 150 100 40 30 20 210 180 160 14C 120 90 80 60 50 1 (ppm) -147.25 13Carboxylic acid-Expansion H CDC 学9999年年99 79 7.75 7,65 7,25 7.70 7,35 7. 06 7 80 7,60 7.5C 7.40 7.30 7.90 7.85 7.55 7.45 f1

Analyst Analyst Friday, 5 April 2019 5:14 PM Date 99 98- 96- 94- 479.98cm-1 591.29cm- 92- 1067.08erh- 542.08cm-1 90- 97222c0 LeT4.55cm-1 71.82om-1 88- 031.55cm-n3 87cm-1 1175.95cm-1 86 1205.05cm-1 84- 1449.50dm- 2592,18cm-1 82- 1419.56cm 3024,78cm-2826.13cm-1 1492.40cm- 80- 1313.32cm-1 1286.88cm-1 1577.39cm-1 78 1628.89cm-1 1677.71cm-t 76- 75 4000 3000 2500 1500 1000 3500 2000 500400 cm.1
Carboxylic acid 1С CDCI, a0 220 200 130 110 10 230 10 170 150 100 40 30 20 210 180 160 14C 120 90 80 60 50 1 (ppm) -147.25 130.90
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ReportAnswer #1

The compound is benzoic acid or C6H5COOH.

COOH peak at 3500 to 2500.

1677 is CO.1286 is C-O.

13C NMR, 177 ppm is carbonyl carbon.rest of the peaks are of aromatic pr benzene carbons.

1H NMR shows ortho meta and para hydrogen's.

Two ortho H show multiplet and para also show multiplet.

Meta shows doublet at 7.8 ppm

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