# Current Attempt in Progress Consider the following discrete random distribution. X P(x) 0 .15 1 25... Current Attempt in Progress Consider the following discrete random distribution. X P(x) 0 .15 1 25 2 .25 3 25 4 .10 What is the variance of the distribution? 5.1 3.61 1.22 1.79 1.49

 x f(x) xP(x) x2P(x) 0 0.1500 0.0000 0.0000 1 0.2500 0.2500 0.2500 2 0.2500 0.5000 1.0000 3 0.2500 0.7500 2.2500 4 0.1000 0.4000 1.6000 total 1.9000 5.1000 E(x) =μ= ΣxP(x) = 1.9000 E(x2) = Σx2P(x) = 5.1000 Var(x)=σ2 = E(x2)-(E(x))2= 1.4900

variance =1.49

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