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8.4.9 Question Help Find the first four nonzero terms in a power series expansion about xo...

8.4.9 Question Help Find the first four nonzero terms in a power series expansion about xo for a general solution to the give

8.4.9 Question Help Find the first four nonzero terms in a power series expansion about xo for a general solution to the given differential equation with the given value for Xo- (x2 - 4x) y" + 6y = 0; xp = 2 + y(x)= (Type an expression in terms of a, and a that includes all terms up to order 3.)
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given differential (1) 6 y = 0. : Here P(x) = 0 & 6 Now differential equation is (x2 - 4x).y + by = 0 = y + o. y + (x²-4x).n.vn=o. Series be & ) n=0 no nso y=5 cn.vn So.Vn-4. n(n-1) Gun-20 Since V=0 is and ordinary point of (11). Let the y- Eng.vv²+ 3.6.12 + 7 4 4 + GV3 +4V +6V8+ 13 + 36 6u4 t. + Therefore, the solution becomes, y=6 + GVTC G+GV + 60.22+ + GV5+ -y-Co. [

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8.4.9 Question Help Find the first four nonzero terms in a power series expansion about xo...
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