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Pease answer questions 4 and 5! Thank you so much! 4. Connect the 2nd resistor in...

Pease answer questions 4 and 5! Thank you so much!



4. Connect the 2nd resistor in parallel with the 1st resistor and connect that combination to the battery.

         Measure the following:

              The current passing through the R1, I1 = ___0.0058____ A

              The current passing through the R2, I2 = ___0.0031____ A

              The current supplied by the battery, I = ___0.0092____ A

             Calculate I1 + I2 = ____________ A

                    Is the following statement true? I = I1 + I2 _____Y or N______

             Calculate the energy delivered by the battery

                                                     = V I = ____________ x ____________

= ___________ Watts

            

Why is the power delivered by the battery greater than in Step 1?  

Answer: __________________________________________________

  __________________________________________________________

  __________________________________________________________

5. Disconnect the battery from the circuit (but leave the two resistors connected in parallel).  

Use the Multimeter to measure the combined resistance of the two resistors connected in parallel:

           Measure the equivalent resistance, R = ___680___ Ohms

           Calculate 1/R, which equals to:

                                          1/R = 1/R1 + 1/R2 = 1/( ) + 1/ ( )

                                                          = __________ + __________

                                                         = ____________

           Calculate R = ____________ Ohms

Is the calculated R and measured R approximately equal to each other?          

____________



For Resistors Connected in Series: In an electric circuit, the equivalent resistance of resistors connected in series is giveProcedures: 1. Using the Multimeter: Use the Multimeter to measure the voltage of a battery, the potential voltage drop acrosR, = Resistance = 2050 Ohms What are the colors of the resistor bands on the resistor? (Starting from the end opposite the go(c) Connect a battery in series with the two resistors using electric wires (.e. the battery and two resistors are connectedIs the sum of the voltages approximately equal to the voltage across the battery? Yes (e) Use the Multimeter at various point2. Verify Ohms Law: Ohms Law states that the current in a series circuit is equal to the value of battery voltage divided b3. Parallel Circuits: (a) Record the values measured in procedures in the previous procedures: = 6.00 Volts Battery voltage RAre the above two values approximately equal to each other? No Calculate how much energy would be consumed by resistor R, in
4. Connect the 2. resistor in parallel with the 1.. resistor and connect that combination to the battery. Measure the followi5. Disconnect the battery from the circuit (but leave the two resistors connected in parallel). Use the Multimeter to measureSchematic of the two circuits we are working with: 4/28/2020 07:51 PM 805 Series 4/28/2020 OT 42 PM 882313 ParallelResistor Color Codes Color Significant figures Multiplier Tolerance 0 Temp. Coefficient (ppm/K) 250 U 100 s 50 R 15 Р +1% F 2

For Resistors Connected in Series: In an electric circuit, the equivalent resistance of resistors connected in series is given by the equation: R=R, + R, + R. +..... The power consumed by a resistor = 1R The power delivered by the power source = VI The power delivered by the power source should be equal to the sum of the power consumed by all the resistors. For Resistors Connected in Parallel: In an electric circuit, the equivalent resistance of resistors connected in parallel is given by the equation: 1/R = 1/R, + 1/R, +1/R, + The power consumed by a resistor = 'R The power delivered by the power source = VI The power delivered by the power source should be equal to the sum of the power consumed by all the resistors.
Procedures: 1. Using the Multimeter: Use the Multimeter to measure the voltage of a battery, the potential voltage drop across a resistor, the current flow in a circuit, and to measure the resistance of a resistor. (a) Measure the resistance of the first resistor (smallest resistance). R, Resistance = 990 Ohms What are the colors of the resistor bands on the resistor? (Starting from the end opposite the gold or silver band) BROWN BLACK RED GOLD What is the resistance of the resistor according to the color bands? (See chart) Resistance = 1000 Ohms, +/- 5% Ohms What is the tolerance of that resistor? 950 Ohms - 1050 Ohms Is the measured value approximately equal to the resistance value according to the color band? Yes (b) Measure the resistance of the second resistor (larger resistance)
R, = Resistance = 2050 Ohms What are the colors of the resistor bands on the resistor? (Starting from the end opposite the gold or silver band) RED BLACK RED GOLD What is the resistance of the resistor according to the color bands (see chart)? Resistance = 2000 Ohms, +/- 5% What is the tolerance of that resistor? 1,900 Ohms - 2100 Ohms Is the measured value approximately equal to the resistance value according to the color band? Yes Series Circuits: (c) Connect the two resistors together in series. Measure the combined resistance of the two resistors. Resistance 2900 Ohms What is the sum of the measured resistances in steps (a) and (b)? 990 Ohms + 2050 Ohms Resistance = 3040 Ohms Is this sum approximately equal to the measured combined resistance? No. However, the +/- 5% tolerance of the resistors can effectively include the measured combined resistance of 2850 Ohms - 3150 Ohms.
(c) Connect a battery in series with the two resistors using electric wires (.e. the battery and two resistors are connected by electric wires to form a closed circular path). What is the voltage between the positive and negative terminals of the battery? Voltage = _ 6.00 volts What is the voltage across the two ends of the first resistor? Voltage = 1.90 volts What is the voltage across the two ends of the second resistor? Voltage = 3.90 volts What is the sum of the two voltages across the two resistors? 1.90 + 3.90 = 5.80 volts Voltage = 5.80 volts Is the sum of the voltages approximately equal to the voltage across the battery? Yes
Is the sum of the voltages approximately equal to the voltage across the battery? Yes (e) Use the Multimeter at various points in the circuit to measure the current (i.e. between the battery and the nearest resistor, and between two resistors). NOTE: The current that you want to measure must run through the Multimeter. Therefore, attach the Multimeter in series with the circuit at the point you want to measure the current. What is the current reading between the battery and the first resistor? Current = 1.90 mA (milliamps) What is the current reading between the first resistor and the 2nd resistor? Current = 1.90 mA (milliamps) What is the current reading between the 2nd resistor and the battery? Current = 1.90 mA (milliamps) Are all the current readings above equal to each other? Yes
2. Verify Ohm's Law: Ohm's Law states that the current in a series circuit is equal to the value of battery voltage divided by the combined resistance in the circuit The voltage of the battery = 6.00V (from step 1(d)) The combined resistance value = 3040 Ohms (from step 1(C)) The quotient between these two values = 6.00 / 3040 = 0.002 Amperes = 0.002 x 1000 = 2.00 mA Is this value approximately equal to the measured current value? (from step 1(e)) Yes 3. Parallel Circuits: (a) Record the values measured in procedures in the previous procedures: Battery voltage Resistor value, R Resistor value, R2 = 6.00 Volts = 990 Ohms = 2050 Ohms = 2.00 mA = 0.002 Amps Current in the series circuit
3. Parallel Circuits: (a) Record the values measured in procedures in the previous procedures: = 6.00 Volts Battery voltage Resistor value, R = 990 Ohms = 2050 Ohms = 2.00 mA = 0.002 Amps Resistor value, R Current in the series circuit Calculate the following: Power delivered by the battery = VI = 6.00 volts x 2.00 mA = 12 Watts Power consumed by the resistor = R, 12 = 990 ohms x (2.00 mA) = 3960 Watts Power consumed by the resistor = R, 12 = 2050 ohms x (2.00 mA) = 8200 Watts
Are the above two values approximately equal to each other? No Calculate how much energy would be consumed by resistor R, in 2 hours? (2 hours = 7200 seconds, Energy = Power x time) Show your computation here: 3960 Watts x 7200 seconds = 28,512,000 Answer = 28,512,000 Joules How many kilowatt-hours is this? (1 kWh = 3,600,000 J) (the lowest rate that the power company charges you is about $0.13 per kilowatt-hour) 28,512,000 + 3,600,000 kWh = 7.92 kWh (kilowatt-hours) 4. Connect the 2nd resistor in parallel with the 1s resistor and connect that combination to the battery. Measure the following: The current passing through the R., I, = 0.0058 A The current passing through the Ry, 12 = 0.0031 A The current supplied by the battery, I 0.0092 A A Calculate 1, + 12 = Is the following statement true? I = 1, + 12 Calculate the energy delivered by the battery
4. Connect the 2. resistor in parallel with the 1.. resistor and connect that combination to the battery. Measure the following: The current passing through the R., 1 = 0.0058 A The current passing through the R., b = 0.0031 A The current supplied by the battery, I 0.0092 A Calculated + 1 = A Is the following statement true? | = 1. + b YorN Calculate the energy delivered by the battery =VI х Watts Why is the power delivered by the battery greater than in Step.1? Answer:
5. Disconnect the battery from the circuit (but leave the two resistors connected in parallel). Use the Multimeter to measure the combined resistance of the two resistors connected in parallel: Measure the equivalent resistance, R 680 Ohms Calculate 1/R, which equals to: 1/R=1/R + 1/R = 1/ ) + 11 ( 11 ) Calculate R = Ohms Is the calculated R and measured R approximately equal to each other?
Schematic of the two circuits we are working with: 4/28/2020 07:51 PM 805 Series 4/28/2020 OT 42 PM 882313 Parallel
Resistor Color Codes Color Significant figures Multiplier Tolerance 0 Temp. Coefficient (ppm/K) 250 U 100 s 50 R 15 Р +1% F 2 +2% G *10° *10 x10² *103 x104 *105 Black Brown Red Orange Yellow Green Blue Violet 3 4 - 25 Q (15%) +0.5% 5 D 20 z 6 x106 +0.25% C N 10 5 *10? 0.1% B M Gray 8 *10 10.05% (+10%) A 1 K 9 *10° J 1 White Gold Silver None *101 *102 +5% +10% +20% к M For example, a resistor with bands of yellow, violet, red, and gold will have the first digit 4 (yellow in table), second digit 7 (violet), followed by 2 (red) zeros: 4,700 ohms. Gold signifies that the tolerance is 15%, so the real resistance could lie anywhere between 4,465 and 4,935 ohms.
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(4) T. +1,= 0.0058 +0.0031 = 0.0089 A Yes I t I, (approximately) VI Energy delivered by battery 6x0.0092 -0.0552 walts Yes, p

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