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Question 11 0/5 points n+1 satisfies all requirements of the Alternating Series Test. (You don't It...

Question 11 0/5 points n+1 satisfies all requirements of the Alternating Series Test. (You dont It 2n=1 have to check that -

Question 11 0/5 points n+1 satisfies all requirements of the Alternating Series Test. (You don't It 2n=1 have to check that - trust me on this one.) (2n+1) (a) Use a calculator to evaluate the partial sum S3 of this series. Give the answer rounded to four decimal places. (b) Estimate the error of using S3 as an approximation to the sum of the series, i.e. estimate the remainder R3. Recall that the remainder estimate of the Alternating Series Test gives an inequality of the form "|Rnl < value". As the answer to this question, provide "value" only, rounded to four decimal places. (c) Considering the error (remainder) estimate from the last part, what can we say about using the partial sum S3 as an approximation to the sum of the infinite series? How many digits of S3 (after the decimal point) do we expect to be correct? As your answer, just say how many digits.
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Now, a,= (-0! S3 = a, + a2 + a2 = 0.01 2 3 46 -0.0016 +0.000 4 16. Given series is Ž (nt no (2011)4 Then an =(-D &.ai S, det

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