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Consider the matrix A and the reduced row echelon form of A. 1 -2 -5 [1...

Consider the matrix A and the reduced row echelon form of A. 1 -2 -5 [1 -2 9 0 4 0 1 3 0 A= 0 3 5 0 -3 3 -3 3 0 0 0 1 Find a

Consider the matrix A and the reduced row echelon form of A. 1 -2 -5 [1 -2 9 0 4 0 1 3 0 A= 0 3 5 0 -3 3 -3 3 0 0 0 1 Find a basis for Nul A.
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Given matrix A and its reduced row echelon form of A - -2 -2 -5 0 A = 3 9 5 3 E3 3 -3 3 The general solution of Ax=0 Null spawhere X3 is free variable. Thus, the vector form solution to Ax=0 is (-483 -4 x = xi X2 X3 24 -343 -3 23 X3 0 It follows that

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Consider the matrix A and the reduced row echelon form of A. 1 -2 -5 [1...
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