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Problem 1. (1 point) A steel ball weighing 128 pounds is suspended from a spring. This stretches the spring 178 feet. The balI AM STRUGGLING HEAVILY ON THIS PROBLEM PLEASE HELP ME WITH THE CORRECT ANSWER AND NEAT WORK PLEASE PLEASE AND THANK YOU

Problem 1. (1 point) A steel ball weighing 128 pounds is suspended from a spring. This stretches the spring 178 feet. The ball is started in motion from the equilibrium position with a downward velocity of 6 feet per second. The air resistance (in pounds) of the moving ball numerically equals times its velocity (in feet per second) Suppose that after t seconds the ball is y feet below its rest position. Find y in terms of t. (Note that this means that the positive direction for y is down.) y = Take as the gravitational acceleration 32 feet per second per second.
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weight 128 feet + of the Steal ball = 128 pounds Strechul the spring The differential equation for the goren my by tky where_ut 16-272 8 8 the initial condition in de a SE -47 V-256 S - - 4+ 161 O acu Si= 2-stui 88 s = -0.5tai The solution to eq (2)Snie C, = 0 6= C2 (2) q=3 from (2) [yos eost Sin (2t)

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