Exponential Graphs IV. Logarithm Graphs y=loght or y=lnx Domain: Domain: Range: Range: Intercept: y-intercept Find the...
State the domain, range, x-intercept(s), y-intercept(s) and asymptote(s) of the given function. https://i.gyazo.com/ad9395dfa1f76d9e60f1346b476bc1ad.png
y= (x^2 + 3x - 4)/ x+4I have to find the holes, asymptopes, zeros, y intercept, domain, rangeAND I am totally clueless. I so don't get this....
Express as a single logarithm. 1. logc t+logc s 2. (loga m-loga n Solve the equations. 1. log4x=log2+log(x-1) 2. log(3+x)-log(x-4)=log 2 3. log2(3x-2)-log2(x-5)=4 4. logx(8/27)=3
Question: find the domain, vertical asymptote, and the x-intercept of f(x)=log(subscript 4)(5-x).
EGR MA / Wins Web IV 6. (5 points each) Find the domain and range for f(r). (a) f(x) -2-(1) (b) f(x) = - +4 (c) f(x) = In(x+1) (d) f(x) = log(x2 - 1) 6
2. (10 points) is the below graph a function? If so find the Domain, Range, X-intercept, Y-intercept. A
7. For each function below, find the intercept(s) (if any) and asymptote(s) (both horizontal and vertical, if any), and then sketch the graph with- out using a calculator; you must properly mark/label the ares, all in- tercept(s), horizontal or vertical asymptote(s) to get full credits: (i) y = 22-1 – 2 (ii) y=1- log2 (x + 2) x-intercept: 2-intercept: y-intercept: y-intercept: Asymptote: Asymptote: Graph: Graph:
y= (x+1)/ x^2 + 3x + 2need to figure out what a graph looks likeis there holeswhat are the asymptotes if anywhat the zeros aredomain and rangewhere increasing decreasingy interceptnegative/positiveodd/ even or neitherI am so new to this and totally lost
How do i solve the functions domain, range, x intercept and y intercept for this function..there is a a shaded dot on (-4,-4) and then theres a curved line going up to an unshaded dot on (0,0)
I need to write 2 equations that represent the same exponential function with a y-intercept of 5 and an asymptote at y=3. I got y=2^(x+1) + 3 but I don't know how to find the second equation. Can someone please explain this to me. Thanks.