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2. [-75 Points] DETAILS SCALCCC4 7.5.007.MI. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER The population of...

2. [-75 Points] DETAILS SCALCCC4 7.5.007.MI. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER The population of the world was about

2. [-75 Points] DETAILS SCALCCC4 7.5.007.MI. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER The population of the world was about 5.3 billion in 1990. Birth rates in the 1990s ranged from 35 to 40 million per year and death rates ranged from 15 to 20 million per year. Let's assume that the carrying capacity for world population is 100 billion. (Assume that the difference in birth and death rates is 20 million/year 0.02 billion/year.) (a) Write the logistic differential equation for these data. (Because the initial population is small compared to the carrying capacity, you can take k to be an estimate of the initial relative growth rate.) dP dt , P in billions (b) Use the logistic model to estimate the world population in the year 2000. (Round the answer to two decimal places.) P= billion (c) Compare with the actual population of 6.1 billion. (Round the answer to one decimal place.) billion. (d) Use the logistic model to predict the world population in the years 2100 and 2500. (Round the answer to two decimal The difference is places.) P= billion in the year 2100 P= billion in the year 2500 Need Help? Read It Master It Talk to a Tutor
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Sonn Population of the world was about 5.3 billion in 1990. Birth Million per year rates in the 1990s ranged from 35 to 40 MiLogistic differential equation + de - K(1-2 substitute ㅗ 265 [ Given that carrying capacity 100 billion) lis & de 245 (1-eveI et te 26500 p2_1000 ttc -265oo (to Un l-p+100) - t In (P)) = - 265 [un (-P+10o) In (P)] = tte t ico Plt) 2 265 e t 265 a с(C) compare with actual population The dioberence is 6.1 billion 0.61 billions Git 5.49 0.61 billions estimated value of popu

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2. [-75 Points] DETAILS SCALCCC4 7.5.007.MI. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER The population of...
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