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Scatter plots and calculating correlation 4. Scatter plots and calculating correlation Aa Aa Suppose you are...

Scatter plots and calculating correlation4. Scatter plots and calculating correlation Aa Aa Suppose you are given the following five pairs of scores: X Y 6 1 9 2 6 3Y 10 Data Points ON 8 7 6 5 4 3 N 1 0 1 2 3 4 5 6 7 8 9 10 X Clear All Based on your scatter plot, you would expect the correNow, using the values for the means that you just calculated, fill out the following table by calculating the deviations fromNow, using the values for the means that you just calculated, fill out the following table by calculating the deviations fromNow, using the values for the means that you just calculated, fill out the following table by calculating the deviations fromNow, using the values for the means that you just calculated, fill out the following table by calculating the deviations fromLook at your scatter plot again. If you excluded the point (1, 10), you would expect the recalculated Pearson correlation to

4. Scatter plots and calculating correlation Aa Aa Suppose you are given the following five pairs of scores: X Y 6 1 9 2 6 3 8 4 10 Create a scatter plot of these scores in the following diagram. For each of the five (X, Y) pairs, click on the plotting symbol (the black x) in the upper right corner of the tool, and drag it to the appropriate location on the grid. Y 10 Data Points Х 9 8 7 6 5 4 3 2 1 0 1 2 3 4 5 6 7 8 8 9 10
Y 10 Data Points ON 8 7 6 5 4 3 N 1 0 1 2 3 4 5 6 7 8 9 10 X Clear All Based on your scatter plot, you would expect the correlation to be The mean X score is Mx = and the mean y score is My =
Now, using the values for the means that you just calculated, fill out the following table by calculating the deviations from the means for X and Y, the squares of the deviations, and the products of the deviations. Scores X Y 6 1 Deviations Squared Deviations Products X - MX Y - My (X - Mx)2 (Y - My) (X - Mx) (Y - My) 9 N 6 3 8 4 1 10 The sum of squared deviations for X is SSX of products is SP = . The sum of squared deviations for Y is ssy = . The sum Because the sign of the sum of products is the sign of the Pearson correlation negative positive The Pearson correlation is r = Look at your scatter plot again. If you excluded the point (1, 10), you would expect the recalculated Pearson correlation to be because
Now, using the values for the means that you just calculated, fill out the following table by calculating the deviations from the means for X and Y, the squares of the deviations, and the products of the deviations. Scores Deviations Squared Deviations Products X Y X - MX Y - My (X - Mx)2 (Y - My) (X - Mx) (Y - My) 6 1 9 2. 6 3 8 4 1 10 II . The sum of squared deviations for Y is SS, . The sum The sum of squared deviations for X is SSx of products is SP = Because the sign of the sum of products is the sign of the Pearson correlation will be positive will be negative depends on the signs of Sex and say The Pear SOIT COITETALIUM IST Look at your scatter plot again. If you excluded the point (1, 10), you would expect the recalculated Pearson correlation to be because
Now, using the values for the means that you just calculated, fill out the following table by calculating the deviations from the means for X and Y, the squares of the deviations, and the products of the deviations. Scores Deviations Squared Deviations Products X Y X - MX Y - My (X - Mx)2 (Y - My) (X - Mx) (Y - My) 6 1 9 2. 6 3 8 4 1 10 II . The sum of squared deviations for Y is SS, . The sum The sum of squared deviations for X is SSx of products is SP = Because the sign of the sum of products is the sign of the Pearson correlation The Pearson correlation is r = -0.03 0.83 -0.83 cluded the point (1, 10), you would expect the recalculated Pearson -1.63 because Look at your scatter plot again correlation to be
Now, using the values for the means that you just calculated, fill out the following table by calculating the deviations from the means for X and Y, the squares of the deviations, and the products of the deviations. Scores X Y Deviations Squared Deviations Products X - MX Y - My (X - Mx)2 (Y - My)2 (X - Mx)(Y - My) 6 1 9 2. 6 لیا 8 4 1 10 . The sum of squared deviations for Y is SS The sum The sum of squared deviations for X is SSx = of products is SP = Because the sign of the sum of products is , the sign of the Pearson correlation The Pearson correlation is r = Look at your scatter plot again. If you excluded the point (1, 10), you would expect the recalculated Pearson correlation to be because different similar
Look at your scatter plot again. If you excluded the point (1, 10), you would expect the recalculated Pearson correlation to be because (1, 10) is an outlier correlation is not the same as causation the relationship between X and Y is nonlinear X and Y are correlated
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12 10 . 8 > 6 4 2 0 0 2 4 6 8 10 We would expect the correlation to be negative. Sample size, n = 5 Ex = 30 Ey = 25 X = Ex/n

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