# Question 5 A steel ball of mass 0.860 kg is fastened to a cord that is... Question 5 A steel ball of mass 0.860 kg is fastened to a cord that is 45.0 cm long and fixed at the far end. The ball is then released when the cord is horizontal, as shown in the figure. At the bottom of its path, the ball strikes a 4.50 kg steel block initially at rest on a frictionless surface. The collision is elastic. Find (a) the speed of the ball and (b) the speed of the block, both just after the collision. (a) Number Unit (b) Number Unit

Let the ball strike the block with a speed u1​. Since the initial speed (speed before collision) of the block =u2​=0 for the perfectly elastic collision, the speed of the block is given as
v2​=(2*m1*u1)/(m1​+m2)
where u1​ can be found by conserving energy of the ball between the position A and B before collision of m1​
⇒1/2*m1u1^2−mgl=0
u1=√(2.10*0.45)=3m/s
From this V2=(2*0.86*3)/(0.86+4.5)=0.963m/s. Is the speed of block after collision

From conservation of momentum

m1u1+m2u2=m1v1+m2v2

0.86*3=(0.86*V1)+(4.5*0.963)

V1=-2.038m/s

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