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A 4 mm high object is placed 9 cm in front of a convex mirror with...

A 4 mm high object is placed 9 cm in front of a convex mirror with radius of curvature 12 cm.

1)The image distance is:

Less than -4 cm

Between 0 and 4 cm

Greater than 4 cm

Between -4 and 0 cm

2) The magnitude of the image height will be:

Between 2 and 4 mm

Greater than 6 mm

Less than 2 mm

Between 4 and 6 mm

3) The image will be:

Real and upright

Virtual and upright

Virtual and inverted

Real and inverted

0 0
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Soln Sign convention 4mm Icm C ft 6cm 12cm Focal length f = 2 12/2 - 6cm Mirror formula I V + te 44 Ve image distance distanchi h >13 3.6cm hi 4x10 cm ما cm h= 0.16cm h = 1.6 mm height of image. tude of image 2 The nu mag image height height will be

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