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Calculate the change in enthalpy (ΔH) for the heat of formation of ethane, C2H6, using Hess' Law and the following reactions:

Calculate the change in enthalpy (ΔH) for the heat of formation of ethane, C2H6, using Hess' Law and the following reactions:


a) 2C(S) + 2O2(g) → 2CO2(g), ΔH = -188 kcal

b) C2H6(g) + (7/2)O2(g) → 2CO2(g) + 3H2O(l), ΔH = -373 kcal

c) H2(g) + (1/2)O2(g) → H2O(l), ΔH = -68.3 kcal

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We have to calculate the change in entha formation of ethane. ralpy for for the The reaction of formation of ethane is, 2 C(s

adding equations 0 , and and (v An = -204 g kcal 2 C(s) + 2 0 Cg) → 2 coz (8) A4, = -188 ocal 342 (g) + 36 (g) > 3 Hole 2002(

According to the Hess' Law of constant heat summation, if we wish to calculate the heat of formation of a product which is formed in multiple steps then the required change in the enthalpy will be sum of change in enthalpies of every individual step.

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Calculate the change in enthalpy (ΔH) for the heat of formation of ethane, C2H6, using Hess' Law and the following reactions:
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