Solve each equation on the interval: 0 is less than and equal to theta is less than and equal to 360 -- 2sin2x = 1 -- --- My Answers: Let y represent 2x 2siny = 1 2siny/2 = 1/2 siny = 1/2 y = sin^-1(1/2) y = 30 2x = 30 2x/2 = 30/2 x = 15 (Quadrant 1
Solve each equation for o is less than and/or equal to theta is less than and/or equal to 360--sin^2x = 1 = cos^2x--Work:cos^2x - cos^2x = 00 = 0--Textbook Answers:90 and 270--Btw, how would you isolate for cos^2x = 0? Would it be...x = cos^-1 square root of _____ ?
Solve the following equation for 0 less than and/or equal to "x" less than and/or equal to 360--cos^2x - 1 = sin^2x--Attempt:cos^2x - 1 - sin^2x = 0cos^2x - 1 - (1 - cos^2x) = 0cos^2x - 1 - 1 + cos^2x = 02cos^2x - 2 = 0(2cos^2x/2)= (-2/2)cos^2x = -1cosx = square root of -1And I can't do anything with this now...what am I doing wrong?--Textbook answers:0, 180, 360--
Solve: 2 sin x - 1 = 0 for 0 degrees is less than or equal to x is less than 360 degrees.
Solve each equation for 0 is less than and equal to "x" is less than and equal to 3603sinx = 2cos^{2}x-----I don't know how to solve this equation...this is what I have, but I don't know if I'm on the right track or not3sinx = 1 - 2sin^{2}x3sinx - 1 + 2sin^{2}x = 02sin^{2}x + 3sinx - 1 = 0sinx(3 + 2sinx) = 1...and if I am, what do I do next now?-----The answers are:30 and 150 degrees
Solve the equation in the given Domain: 1-cos theta/ sin theta = sqr3, 0degrees <or equal to theta < 369 degrees cos4x + cos 2x =0, 0<or equal to x < pi
For which angles beta, with 0 degrees less than/equal to beta less than/equal to 180 degrees,is sin 3beta equal to -1?a) 30 degress and 150 degreesb) 60 and 120 degreesc) 90 degreesd) 0 and 120 degreesI think it is C because sin of (3 x 90 = 270) 270 degrees is -1?Did I do this right? Or did I do something that cannot be done?Thank you.
Find the value of x in the interval 0 is less than or equal to x and 360 is greater than or equal to x which satisfies the equation cos x - 2 cos x sin x.
Solve for x where x is a real number, sin 2x = sin x, 0 less than or equal to x less than or equal to 2 pi
Solve the inequality:2x-1 / 3x-2 < 1[the < is actually less than or equal to]I got one of the answers, x is less than or equal to 1, but there's another. How do you find that answer?Thanks
Solve each equation if the domain of x is {-1, 0, 2} 2x + y = -3