Solve each equation for 0 is less than and equal to "x" is less than and equal to 360 3sinx = 2cos^{2}x ----- I don't know how to solve this equation
Solve the following equation for 0 less than and/or equal to "x" less than and/or equal to 360--cos^2x - 1 = sin^2x--Attempt:cos^2x - 1 - sin^2x = 0cos^2x - 1 - (1 - cos^2x) = 0cos^2x - 1 - 1 + cos^2x = 02cos^2x - 2 = 0(2cos^2x/2)= (-2/2)cos^2x = -1cosx = square root of -1And I can't do anything with this now...what am I doing wrong?--Textbook answers:0, 180, 360--
solve each equation for 0=/<x=/<2pisin^2x + 5sinx + 6 = 0?how do i factor this and solve?2sin^2 + sinx = 0(2sinx - 3)(sinx +2)sinx = 3/2, -2how do I solve? These are not part of the special triangles.2cos^2 - 7cosx + 3 = 0(2cosx - 1)(cosx - 3)cosx = 1/2, 3x= pi/4, 7pi/4, how do I find solve for 3?thanks in advance
the problem is 2cos^2x + sinx-1=0the directions are to "use an identity to solve each equation on the interval [0,2pi).This is what i've done so far:2cos^2x+sinx-1=02cos^2x-1+sinx=0cos2x + sinx =01 - 2sin^2x + sinx = 0-2sin^2x+sinx-1=02sin^2x-sinx+1=0I think i'm supposed to factor it next but i'm not sure?(2sinx-?)(sinx-?) would doing that step be correct?
Solve: 2 sin x - 1 = 0 for 0 degrees is less than or equal to x is less than 360 degrees.
y= 2sin^2 x y=1- sinx find values of x inthe interval 0<x<360if 2sin^x = 1-sinx this can be arranged into the quadratic. 2sin^2 x + sin x -1=0 (2sinx -1)(sinx + 1)=0 or sinx = 1/2 and sin x=-1
Solve each equation on the interval:0 is less than and equal to theta is less than and equal to 360--2sin2x = 1-----My Answers:Let y represent 2x2siny = 12siny/2 = 1/2siny = 1/2y = sin^-1(1/2)y = 302x = 302x/2 = 30/2x = 15 (Quadrant 1)Quadrant 2180 - theta= 180 - 30= 1502x = 1502x/2 = 150/2x = 75Therefore, x = 15 and 75 degrees---Book's Answers:15, 75, 195, 255---My Problem:I'm asking how do you get 195 and 255 degrees if the equation...
Solve to the nearest minute: x is greater than or equal to 0 and less than 360.3sec^2 x-8tan-6=cotx
Solve: sin2 x = cos2 x for 0 degrees is less than or equal to x is less than 360 degrees.
solve the equationsin(3x) + (1/2) = 2cos^2(x)for X to be between 0 and 360
trig question2sin^2x+sinx-6=0how to solve for x when the restriction is x is greater than or equal to zero but less than 2pi