Solve each equation for o is less than and/or equal to theta is less than and/or equal to 360 -- sin^2x = 1 = cos^2x -- Work: cos^2x - cos^2x = 0 0 = 0 -- Textbook Answers: 90 and 270 -- Btw, how would you isolate for cos^2x = 0
Solve the following equation for 0 less than and/or equal to "x" less than and/or equal to 360--cos^2x - 1 = sin^2x--Attempt:cos^2x - 1 - sin^2x = 0cos^2x - 1 - (1 - cos^2x) = 0cos^2x - 1 - 1 + cos^2x = 02cos^2x - 2 = 0(2cos^2x/2)= (-2/2)cos^2x = -1cosx = square root of -1And I can't do anything with this now...what am I doing wrong?--Textbook answers:0, 180, 360--
Solve each equation on the interval:0 is less than and equal to theta is less than and equal to 360--2sin2x = 1-----My Answers:Let y represent 2x2siny = 12siny/2 = 1/2siny = 1/2y = sin^-1(1/2)y = 302x = 302x/2 = 30/2x = 15 (Quadrant 1)Quadrant 2180 - theta= 180 - 30= 1502x = 1502x/2 = 150/2x = 75Therefore, x = 15 and 75 degrees---Book's Answers:15, 75, 195, 255---My Problem:I'm asking how do you get 195 and 255 degrees if the equation...
Solve the equation in the given Domain: 1-cos theta/ sin theta = sqr3, 0degrees <or equal to theta < 369 degrees cos4x + cos 2x =0, 0<or equal to x < pi
solve each equation for 0 ≤ theta < 2pi: 2 cos theta =- square root 3 sin theta + cos theta?
How do I solve Cos(theta)= 3/7 if 0 degrees is less than or equal to theta and theta is less than or equal to 90 degrees?
Solve: 2 sin x - 1 = 0 for 0 degrees is less than or equal to x is less than 360 degrees.
Find the value of x in the interval 0 is less than or equal to x and 360 is greater than or equal to x which satisfies the equation cos x - 2 cos x sin x.
Solve each equation for 0 is less than and equal to "x" is less than and equal to 3603sinx = 2cos^{2}x-----I don't know how to solve this equation...this is what I have, but I don't know if I'm on the right track or not3sinx = 1 - 2sin^{2}x3sinx - 1 + 2sin^{2}x = 02sin^{2}x + 3sinx - 1 = 0sinx(3 + 2sinx) = 1...and if I am, what do I do next now?-----The answers are:30 and 150 degrees
Solve the equation if 0 is less than or equal to x and x is less than 2 pie 2sin^2x+3 cos x -3 0
Let sin alpha = 5/13 where 90° is less than or equal to alpha is less than or equal to 180° and cos beta = -24/25 where 180° is less than or equal to beta is less than or equal to 270° Find cos (alpha - beta) and tan (alpha + beta)